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Is 1/(a-b) < (b - a)? (1) a < b (2) 1 < abs(a-b

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Joined: 03 Feb 2009
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Schools: Duke, UNC, Emory, Ga Tech, Vanderbilt, Indiana, Wash U, Texas, Rollins
Is 1/(a-b) < (b - a)? (1) a < b (2) 1 < abs(a-b [#permalink]

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New post 03 Mar 2009, 12:03
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A
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D
E

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Is 1/(a-b) < (b - a)?

(1) a < b
(2) 1 < abs(a-b)

Kudos [?]: 22 [0], given: 0

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Kudos [?]: 19 [1], given: 5

Re: DS: Inequality [#permalink]

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New post 03 Mar 2009, 12:34
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I think its A.

As the first statement tells that LHS is less than the right hand side of the inequality under the rule a<b.
If you try it with numbers like:
a=2 & b=4

1/(2-4) < 4-2
-1/2 < 2
so its sufficient.

Under the second rule of 1<abs(a-b). if we use the values above:

if a=4 & b =2

1< abs(4-2) and thus get 1<2.

However if we use a=2 and b=4

1<abs (2-4) we still get 1 <2

So we cant really tell what the values of a & b are and whether they are negative or positive and thus the its not sufficient, as the abs value only tells the distant from the middle or or from 0.

So the Ans is A.

Hope that helps mate.

JF 8-)

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Schools: Duke, UNC, Emory, Ga Tech, Vanderbilt, Indiana, Wash U, Texas, Rollins
Re: DS: Inequality [#permalink]

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New post 03 Mar 2009, 13:04
Thanks. I see it. Well done.

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Re: DS: Inequality [#permalink]

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New post 03 Mar 2009, 14:01
bmiller0731 wrote:
Is 1/(a-b) < (b - a)?

(1) a < b
(2) 1 < abs(a-b)



a<b --> a-b<0
also b-a>0

1/(a-b) <0 clearly 1/(a-b)< (b-a) which is positive

A.
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Smiling wins more friends than frowning

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Re: DS: Inequality   [#permalink] 03 Mar 2009, 14:01
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