Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options. - Dec 21
11:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
06 Feb 2020, 09:34
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (00:52) correct
15%
(00:21)
wrong
based on 34
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(a > 0?\)
(1) \(ab= 25\)
(2) \(\sqrt{b}>1\)
(1) \(ab= 25\)
(2) \(\sqrt{b}>1\)
GMATBuster's Collection
06 Feb 2020, 20:37
Kudos
Bookmarks
Hi,
I have taken the following approach to solve this question. Please correct me if I am wrong.
question: Is a>0?
We can solve this question by Picking numbers.
Let us consider the statements.
Statement 1:-
\(ab=25\)
Product of two numbers can be 25 in multiple ways:-
\( a*b=25\)
\( 1*25=25\) , here a > 0
\( (-1)*(-25)=25\), here a <0
So here we are not getting a definite answer regarding whether a > 0 or not.
So we can eliminate options A and D.
Statement 2:-
\(\sqrt{b} > 1\)
Squaring both sides, we get
\(b > 1\)
Here we don't have any information about a.
So we can eliminate option B.
Considering statements 1 & 2 together,
From statement 1 we know that \(a*b=25\)
now since the product is positive, so both a & b should be of same sign i.e either both a & b positive or both a & b negative and neither of them is 0.
From statement 2, we get that b is positive, so a should also be positive.
So on considering both the statements together we can definitely say that a>0.
Hence, option C is correct.
I have taken the following approach to solve this question. Please correct me if I am wrong.
question: Is a>0?
We can solve this question by Picking numbers.
Let us consider the statements.
Statement 1:-
\(ab=25\)
Product of two numbers can be 25 in multiple ways:-
\( a*b=25\)
\( 1*25=25\) , here a > 0
\( (-1)*(-25)=25\), here a <0
So here we are not getting a definite answer regarding whether a > 0 or not.
So we can eliminate options A and D.
Statement 2:-
\(\sqrt{b} > 1\)
Squaring both sides, we get
\(b > 1\)
Here we don't have any information about a.
So we can eliminate option B.
Considering statements 1 & 2 together,
From statement 1 we know that \(a*b=25\)
now since the product is positive, so both a & b should be of same sign i.e either both a & b positive or both a & b negative and neither of them is 0.
From statement 2, we get that b is positive, so a should also be positive.
So on considering both the statements together we can definitely say that a>0.
Hence, option C is correct.
06 Feb 2020, 20:58
Kudos
Bookmarks
It is the Right approach
varmashreekanth
Hi,
I have taken the following approach to solve this question. Please correct me if I am wrong.
question: Is a>0?
We can solve this question by Picking numbers.
Let us consider the statements.
Statement 1:-
\(ab=25\)
Product of two numbers can be 25 in multiple ways:-
\( a*b=25\)
\( 1*25=25\) , here a > 0
\( (-1)*(-25)=25\), here a <0
So here we are not getting a definite answer regarding whether a > 0 or not.
So we can eliminate options A and D.
Statement 2:-
\(\sqrt{b} > 1\)
Squaring both sides, we get
\(b > 1\)
Here we don't have any information about a.
So we can eliminate option B.
Considering statements 1 & 2 together,
From statement 1 we know that \(a*b=25\)
now since the product is positive, so both a & b should be of same sign i.e either both a & b positive or both a & b negative and neither of them is 0.
From statement 2, we get that b is positive, so a should also be positive.
So on considering both the statements together we can definitely say that a>0.
Hence, option C is correct.
I have taken the following approach to solve this question. Please correct me if I am wrong.
question: Is a>0?
We can solve this question by Picking numbers.
Let us consider the statements.
Statement 1:-
\(ab=25\)
Product of two numbers can be 25 in multiple ways:-
\( a*b=25\)
\( 1*25=25\) , here a > 0
\( (-1)*(-25)=25\), here a <0
So here we are not getting a definite answer regarding whether a > 0 or not.
So we can eliminate options A and D.
Statement 2:-
\(\sqrt{b} > 1\)
Squaring both sides, we get
\(b > 1\)
Here we don't have any information about a.
So we can eliminate option B.
Considering statements 1 & 2 together,
From statement 1 we know that \(a*b=25\)
now since the product is positive, so both a & b should be of same sign i.e either both a & b positive or both a & b negative and neither of them is 0.
From statement 2, we get that b is positive, so a should also be positive.
So on considering both the statements together we can definitely say that a>0.
Hence, option C is correct.
