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# Is mn<10?

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Intern
Joined: 25 Oct 2014
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11 Oct 2015, 00:23
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75% (hard)

Question Stats:

46% (02:05) correct 54% (00:45) wrong based on 247 sessions

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Is mn < 10?

(1) m < 5 and n < 2
(2) 1 < m < 3 and n^2<25
[Reveal] Spoiler: OA

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11 Oct 2015, 04:21
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Srav wrote:
Q. Is mn < 10?

(1) m < 5 and n < 2
(2) 1 < m < 3 and n^2<25

Per statement 1, m<5 and n<2 ---> no if m=-10, n = -5 but yes if m=1 and n =1 . Not sufficient

Per statement 2, 1<m<3 and $$n^2<25$$ ----> 1<m<3 and -5<n<5. Again you get 2 different answers for (m,n)=(2.9,4) or (1.5,-1). Thus not sufficient.

Combining the 2 statements you get, 1<m<3 and -5<n<2, giving you -15<mn<6 and thus you get an unambiguous "no" and hence C is the correct answer.
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25 Jan 2017, 01:09
unless it is stated that m, n are integers shouldnt the answer be E?

m=2.99 n=4 mn> 10,
so shouldnt the answer be E?

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25 Jan 2017, 04:02
krisnaren2010 wrote:
unless it is stated that m, n are integers shouldnt the answer be E?

m=2.99 n=4 mn> 10,
so shouldnt the answer be E?

Hi krisnaren2010,

By combining statement 1 and 2 we have following:

1<m<3 and -5<n<2 .

So, you can't take n = 4.

Hope it helps.
Thanks.

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27 Jan 2017, 05:43
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Hi Srav,

The best thing to do while solving questions of this type is to make use of the Max/Min Concept of Inequalities.

If we are given two ranges say -11 < x < 9 and -9 < y < 2 and the question asks us to find the max and min values of x * y then we can place the ranges one below the other and find the values for x * y for the 4 extreme values i.e. -11, 9, -9 and 2.

The four extreme values of x * y are 99, 18, -22 and -81. So -81 < xy < 99.

To apply the max min concept we need to keep in mind that the inequalities of the two ranges are the same. If they are not then we manipulate the numbers or use the properties of inequalities to make them the same. This same procedure can also be used to find the extreme values of x + y and x - y.

So where do we use the max min concept?

Whenever we have been given two ranges, one for x and the other for y (with the same inequality sign) and the question asks us to find the value of x + y, x - y and x * y.

Now coming to the question given

Is mn < 10?

(1) m < 5 and n < 2
(2) 1 < m < 3 and n^2 < 25

Statement 1 : Clearly insufficient as m can be 4 and n can be 1, which gives us a YES for mn < 10 or m can be -5 and n can be -2 which gives us a NO for mn < 10.

Statement 2 : 1 < m < 3 and n^2 < 25

Now here we can apply the max min concept, since 1 < m < 3 and -5 < n < 5. Multiplying the extreme values we get -5, 5, 15 and -15. So the range here is -15 < mn < 15. Insufficient.

Combining statements 1 and 2 : The range for m is 1 < m < 3 and the range for n is -5 < n < 2.

Again applying the max min concept we get -15 < mn < 6. Since mn here will always be less than 10. Sufficient.

Hope this helps!

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http://gmat.crackverbal.com/free-resources/ebook-library/

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15 Apr 2017, 18:24
Srav wrote:
Is mn < 10?

(1) m < 5 and n < 2
(2) 1 < m < 3 and n^2<25

Statement 1
m < 5 and n < 2

m could be (-7) and n could be (-6) which would result in a number greater than ten; however,
m could be (-7) and n could be (1) which would result in a number less than ten.

Insufficient.

Statement 2

1<2.7<3 and (4)^2 equals a number greater than ten

1<2<3 and (4)^2 equals a number less than ten

Statement 1 and Statement 2

1<m<4 subsumes a value less than five

(-4)<n<2 contains a number that when squared is less than 25 and less than 2

The product of each and every combination that can be formed from both sets is less than ten (e.g the product of 2.7 and 1 is less than 10)

Sufficient.

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22 Apr 2017, 08:12
Srav wrote:
Is mn < 10?

(1) m < 5 and n < 2
(2) 1 < m < 3 and n^2<25

What is the source? Good question.
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22 Apr 2017, 09:03
ashikaverma13 wrote:
Srav wrote:
Is mn < 10?

(1) m < 5 and n < 2
(2) 1 < m < 3 and n^2<25

What is the source? Good question.

Check source in the tags above the original post. It's Veritas Prep.
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19 Jul 2017, 08:21
Srav wrote:
Is mn < 10?

(1) m < 5 and n < 2
(2) 1 < m < 3 and n^2<25

(1) $$m < 5$$ and $$n < 2$$

Lets try some numbers.

$$m = 4; n = 1$$
$$mn = (4*1) = 4 < 10$$

$$m = -6; n = -2$$
$$mn = (-6*-2) = 12 > 10$$

Hence I is Not Sufficient.

(2) $$1 < m < 3$$ and $$n^2<25$$

$$m = 2; n = 4$$
$$mn = (2*4) = 8 < 10$$

$$m = 2.9; n = 4$$
$$mn = (2.9*4) = 11.6 > 10$$

Hence II is Not Sufficient.

Combining I and II

Value of $$m$$ is between $$=> 1 < m < 3$$

$$n^2 < 25$$
$$-5 < n < +5$$
From (1) $$n < 2$$
Therefore; Value of $$n$$ is between $$=> -5 < n < 2$$

Checking minimum and maximum value of $$mn$$;

Minimum value of $$mn > (3*-5) = -15$$
Maximum value of $$mn < (3*2) = 6$$
$$-15<mn<6$$

Therefore $$mn<10$$

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Re: Is mn<10?   [#permalink] 19 Jul 2017, 08:21
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