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# is p + q > 0? 1. p / (p+q) > 0 2. q / (p+q) > 0

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CEO
Joined: 15 Aug 2003
Posts: 3452

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is p + q > 0? 1. p / (p+q) > 0 2. q / (p+q) > 0 [#permalink]

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08 Jan 2004, 11:01
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is p + q > 0?

1. p / (p+q) > 0

2. q / (p+q) > 0

Kudos [?]: 925 [0], given: 781

Director
Joined: 28 Oct 2003
Posts: 501

Kudos [?]: 34 [0], given: 0

Location: 55405

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08 Jan 2004, 11:34
My brain says E but my gut says that I'm missing something...

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Senior Manager
Joined: 05 May 2003
Posts: 424

Kudos [?]: 12 [0], given: 0

Location: Aus

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08 Jan 2004, 12:06
Even I feel the answer should be E.

1. p / (p+q) > 0
for example, p=-4 and q=2 then p/(p+q) is positive but p+q is negative
p=4 and q=2 then p/(p+q) and p+q are positive
So, insufficient
2. q / (p+q) > 0
for example, p=2 and q=-4 then p/(p+q) is positive but p+q is negative
p=2 and q=2 then p/(p+q) and p+q are positive
So, insufficient

Both together also doesn't seems to give the answer.

Kudos [?]: 12 [0], given: 0

SVP
Joined: 30 Oct 2003
Posts: 1788

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Location: NewJersey USA

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09 Jan 2004, 20:20
p/(p+q) > 0 if p is -ve then (p+q) is -ve
same holds good for q/(p+q)
I think it should be E.

If it is from kaplan then C.
because p/(p+q) > 0 means p >0 and same holds good for q.

so p+q > 0

Kudos [?]: 114 [0], given: 0

CEO
Joined: 15 Aug 2003
Posts: 3452

Kudos [?]: 925 [0], given: 781

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10 Jan 2004, 06:38
anandnk wrote:
p/(p+q) > 0 if p is -ve then (p+q) is -ve
same holds good for q/(p+q)
I think it should be E.

If it is from kaplan then C.
because p/(p+q) > 0 means p >0 and same holds good for q.

so p+q > 0

Kudos [?]: 925 [0], given: 781

Manager
Joined: 28 Jan 2004
Posts: 202

Kudos [?]: 29 [0], given: 4

Location: India

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30 Jan 2004, 06:07
Lets do it by applying the basics.
If A>X and B>Z then ,A + B > X + Z
applyinh this we will get 1>0 so it is true, by using both.
Ans. is C. (A and B are ruled out correctly by others)

Kudos [?]: 29 [0], given: 4

Director
Joined: 28 Oct 2003
Posts: 501

Kudos [?]: 34 [0], given: 0

Location: 55405

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30 Jan 2004, 07:22
Say P and q are both negative.

1) a negative over a negative is a greater than zero, true.
2) a negative over a negative is a greater than zero, true.

Say P and q are both positive

1) a positive over a positive is a greater than zero, true.
2) a positive over a positive is a greater than zero, true.

So, all of these equations can potentially be true whether both terms are positive or negative.

E.

Kudos [?]: 34 [0], given: 0

30 Jan 2004, 07:22
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