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Is x < 1?

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ganand
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Is x < 1? [#permalink] New post   06 May 2017, 05:09
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35% (medium)

Question Stats:

68% (01:20) correct 32% (01:07) wrong based on 73 sessions
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Is \(x < 1\)?

(1) \(x^{2}\) is greater than \(x\).

(2) \(x^{3}\) is positive.


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C
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stonecold
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Re: Is x < 1? [#permalink] New post   06 May 2017, 05:21
We need to see if x<1 or not.

Statement 1 ->
x^2>x

x<0
or
x>1

Not sufficient

Statement 2 =>

x>0

Not sufficient

Combing the two statements => x>1

Hence we have a definite NO for x<1

Thus x is never less than 1

Sufficient

SMASH THAT C
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Alexey1989x
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Re: Is x < 1? [#permalink] New post   06 May 2017, 05:23
Need to figure out if x-1<0
(1) x^2-x>0
x(x-1)>0
It happens only when x and x-1 have the same signs. As long as we have two cases x can be more or less than 1.
Insufficient
(2) x^3>0, hence x is positive by itself however from this statement we cannot deduce whether x<1
Insufficient
(1)+(2) We can cross out negative case from statement (1) and we are left with x(x-1)>0, which means that x>1 and the answer to the main question will be NO

C
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Re: Is x < 1? [#permalink] New post   06 May 2017, 05:52
Is x < 1?

1) \(x^2\) > x
2) \(x^3\) > 0

Considering Statement 1 alone:
\(x^2\) > x
This is true for x > 1 and also for x < 0........INSUFFICIENT
AD out, BCE stays.

Considering statement 2 alone:
\(x^3\) > 0
=> x > 0, so can be < 1 and > 1............INSUFFICIENT

Considering both the statements together:
Both statements hold true only when x > 1.
SUFFICIENT.

The answer is C.
GMAT Club Bot
gmatclubot
Re: Is x < 1? [#permalink]
06 May 2017, 05:52
Moderator:
Bunuel
Math Expert
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