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# Is x < 1?

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Manager
Joined: 17 May 2015
Posts: 210

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06 May 2017, 04:09
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Difficulty:

45% (medium)

Question Stats:

56% (01:10) correct 44% (00:48) wrong based on 54 sessions

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Is $$x < 1$$?

(1) $$x^{2}$$ is greater than $$x$$.

(2) $$x^{3}$$ is positive.

[Reveal] Spoiler: OA
Retired Moderator
Joined: 12 Aug 2015
Posts: 2415
GRE 1: 323 Q169 V154
Re: Is x < 1? [#permalink]

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06 May 2017, 04:21
We need to see if x<1 or not.

Statement 1 ->
x^2>x

x<0
or
x>1

Not sufficient

Statement 2 =>

x>0

Not sufficient

Combing the two statements => x>1

Hence we have a definite NO for x<1

Thus x is never less than 1

Sufficient

SMASH THAT C

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Senior Manager
Joined: 05 Dec 2016
Posts: 263
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: Is x < 1? [#permalink]

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06 May 2017, 04:23
Need to figure out if x-1<0
(1) x^2-x>0
x(x-1)>0
It happens only when x and x-1 have the same signs. As long as we have two cases x can be more or less than 1.
Insufficient
(2) x^3>0, hence x is positive by itself however from this statement we cannot deduce whether x<1
Insufficient
(1)+(2) We can cross out negative case from statement (1) and we are left with x(x-1)>0, which means that x>1 and the answer to the main question will be NO

C
Intern
Status: Not Applying
Joined: 27 Apr 2009
Posts: 40
Location: India
Schools: HBS '14 (A)
GMAT 1: 760 Q51 V41
Re: Is x < 1? [#permalink]

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06 May 2017, 04:52
Is x < 1?

1) $$x^2$$ > x
2) $$x^3$$ > 0

Considering Statement 1 alone:
$$x^2$$ > x
This is true for x > 1 and also for x < 0........INSUFFICIENT

Considering statement 2 alone:
$$x^3$$ > 0
=> x > 0, so can be < 1 and > 1............INSUFFICIENT

Considering both the statements together:
Both statements hold true only when x > 1.
SUFFICIENT.

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Re: Is x < 1?   [#permalink] 06 May 2017, 04:52
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