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06 May 2017, 05:09
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Is \(x < 1\)?
(1) \(x^{2}\) is greater than \(x\).
(2) \(x^{3}\) is positive.
Source: Self-made
(1) \(x^{2}\) is greater than \(x\).
(2) \(x^{3}\) is positive.
Source: Self-made
stonecold
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Joined: 12 Aug 2015
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Schools: Boston U '20 (M)
GRE 1: Q169 V154
06 May 2017, 05:21
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We need to see if x<1 or not.
Statement 1 ->
x^2>x
x<0
or
x>1
Not sufficient
Statement 2 =>
x>0
Not sufficient
Combing the two statements => x>1
Hence we have a definite NO for x<1
Thus x is never less than 1
Sufficient
SMASH THAT C
Statement 1 ->
x^2>x
x<0
or
x>1
Not sufficient
Statement 2 =>
x>0
Not sufficient
Combing the two statements => x>1
Hence we have a definite NO for x<1
Thus x is never less than 1
Sufficient
SMASH THAT C
06 May 2017, 05:23
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Need to figure out if x-1<0
(1) x^2-x>0
x(x-1)>0
It happens only when x and x-1 have the same signs. As long as we have two cases x can be more or less than 1.
Insufficient
(2) x^3>0, hence x is positive by itself however from this statement we cannot deduce whether x<1
Insufficient
(1)+(2) We can cross out negative case from statement (1) and we are left with x(x-1)>0, which means that x>1 and the answer to the main question will be NO
C
(1) x^2-x>0
x(x-1)>0
It happens only when x and x-1 have the same signs. As long as we have two cases x can be more or less than 1.
Insufficient
(2) x^3>0, hence x is positive by itself however from this statement we cannot deduce whether x<1
Insufficient
(1)+(2) We can cross out negative case from statement (1) and we are left with x(x-1)>0, which means that x>1 and the answer to the main question will be NO
C
