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Is x = 3? (1) (x - 4)(x - 3)/(x - 3) = 0 (2) (x – 4)(x + 4) = 0

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peacewarriors
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Is x = 3? (1) (x - 4)(x - 3)/(x - 3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   Updated on: 15 Jun 2020, 23:58
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Is x = 3?

(1) (x - 4)(x - 3)/(x - 3) = 0
(2) (x – 4)(x + 4) = 0

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why isn't Statement 2 also sufficient,i.e. D
for statement 2 we know that x=-4 or 4 so it is confirmed that x is not equal to 3
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D

Originally posted by peacewarriors on 08 Jul 2014, 01:55.
Last edited by Bunuel on 15 Jun 2020, 23:58, edited 3 times in total.
Renamed the topic and edited the question.
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Re: Is x = 3? (1) (x - 4)(x - 3)/(x - 3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   08 Jul 2014, 02:07
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anujpadia wrote:
Is x = 3?

(1) (x - 4)(x - 3)/(x - 3) = 0
(2) (x – 4)(x + 4) = 0

why isn't Statement 2 also sufficient,i.e. D
for statement 2 we know that x=-4 or 4 so it is confirmed that x is not equal to 3


You are right the answer should be D. What is the source of the question?
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Re: Is x = 3? (1) (x - 4)(x - 3)/(x - 3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   08 Jul 2014, 02:10
The question is from NOVA prep.
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Re: Is x = 3? (1) (x - 4)(x - 3)/(x - 3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   08 Jul 2014, 03:02
For the first statement x=3 is correct but the second statement x=3 is not correct....
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Re: Is x = 3? (1) (x - 4)(x - 3)/(x - 3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   08 Jul 2014, 03:06
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australia123 wrote:
For the first statement x=3 is correct but the second statement x=3 is not correct....


x cannot be 3 for neither of the statements.

(1) (x - 4)(x - 3)/(x - 3) = 0 --> x = 4. x cannot be 3 because in this case the denominator becomes 0 and we cannot divide by 0.

(2) (x – 4)(x + 4) = 0 --> x = 4 or x = -4. So, x is not 3.
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Re: Is x = 3? (1) (x - 4)(x - 3)/(x - 3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   08 Jul 2014, 03:09
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peacewarriors wrote:
Is x = 3?

(1) (x - 4)(x - 3)/(x - 3) = 0
(2) (x – 4)(x + 4) = 0

why isn't Statement 2 also sufficient,i.e. D
for statement 2 we know that x=-4 or 4 so it is confirmed that x is not equal to 3



Both sufficient independently.

Statement (1) x=3 would lead to a 0/0 problem which can not be equal to 0. as 0/0 is undetermined. => x is not equal 3
Statement (2) x= 4 or -4. X can not equal 3
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Re: Is x = 3? (1) [(X-3)(X-4)]/(X-3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   28 Sep 2019, 07:54
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SajjadAhmad wrote:
Is \(x = 3\)?

(1) \(\frac{(x-3)(x-4)}{(x-3)} = 0\)

(2) \((x – 4)(x + 4) = 0\)

Source: Nova GMAT



Dear SajjadAhmad,
Please provide the OE if Ans is A or check the OA
Statement (2) x=4 or x=-4 hence x is NOT equal to 3 hence we have a definite NO. This should be sufficient too, unless I am missing something.
Statement (1) X cannot be 3 because denominator will become 0 hence Suff.
Ans- D
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Re: Is x = 3? (1) [(X-3)(X-4)]/(X-3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   28 Sep 2019, 08:10
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SajjadAhmad, I agree with stne that answer must be D.

(1) x is NEVER equal to 3 due to non-zero requirement for a denominator.
SUFFICIENT

(2) x=-4 or x=4. so, x is NEVER equal to 3.
SUFFICIENT.

Final answer is (D)

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Re: Is x = 3? (1) [(X-3)(X-4)]/(X-3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   28 Sep 2019, 08:13
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chondro48 wrote:
SajjadAhmad, I agree with stne that answer must be D.

(1) x is NEVER equal to 3 due to non-zero requirement for a denominator.
SUFFICIENT

(2) x=-4 or x=4. so, x is NEVER equal to 3.
SUFFICIENT.

Final answer is (D)

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You are both right. Edited the OA. It's D, not A.
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Re: Is x = 3? (1) [(X-3)(X-4)]/(X-3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   28 Sep 2019, 09:59
Why isn't it B ?
I didn't understand why will we get answer from A?
Bunuel

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Re: Is x = 3? (1) [(X-3)(X-4)]/(X-3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink] New post   28 Sep 2019, 10:03
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nishthagupta wrote:
Why isn't it B ?
I didn't understand why will we get answer from A?
Bunuel

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If x were 3 in (1), then we'd get something divided by 0, and anything/0 is undefined (division by 0 is not allowed). So, x is definitely not 3.
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Re: Is x = 3? (1) [(X-3)(X-4)]/(X-3) = 0 (2) (x – 4)(x + 4) = 0 [#permalink]
28 Sep 2019, 10:03
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