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Re: It costs x dollars each to make the first 1,000 copies of a compact [#permalink]
I got E, but this is one where I, again, need to read the problem better. I misread the question and didn't realize x is the price per copy for the first thousand. I thought X was total cost, which led me to X + (Z-1000)*Y, which thankfully isn't an answer.

So I regrouped and realized X is price per copy.
-1000x is the cost of the first 1,000 copies.
-y*(z-1,000) is the cost for every copy after the first 1,000.
-But 1,000x+y*(z-1,000), isn't an answer.
-So I broke expanded outside the parentheses to get 1,000x+yz-1,000y.
-Regrouped the terms to read 1,000x-1,000y+yz.
-Factored out 1,000(x-y)+yz, which is an answer.
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Re: It costs x dollars each to make the first 1,000 copies of a compact [#permalink]
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Bunuel wrote:
It costs x dollars each to make the first 1,000 copies of a compact disc and y dollars to make each subsequent copy. If z is greater than 1,000, how many dollars will it cost to make z copies of the compact disc?

(A) 1,000x + yz
(B) zx – zy
(C) 1,000 (z – x) + xy
(D) 1,000 (z – y) + xz
(E) 1,000 (x – y) + yz


The cost is:

1000x + y(z - 1000)

1000x + yz - 1000y

1000(x - y) + yz

Answer: E
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Re: It costs x dollars each to make the first 1,000 copies of a compact [#permalink]
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Re: It costs x dollars each to make the first 1,000 copies of a compact [#permalink]
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