Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1310:00 AM EST
-12:00 PM EST
Have you ever wondered how to score a PERFECT 805 on the GMAT? Meet Julia, a banking professional who used the Target Test Prep course to achieve this incredible feat. Julia's story is nothing short of an inspiration.
Dec 1207:30 AM PST
-08:30 AM PST
Join the conversation to learn more about INSEAD vs LBS
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
Dec 1411:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- Dec 15
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. - Dec 16
08:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes! - Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
05 May 2022, 08:45
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (02:18) correct
27%
(02:38)
wrong
based on 90
sessions
History
Date
Time
Result
Not Attempted Yet
Jason drives to his parents' house and back home the same way. On the way to his parents' house, his speed is 10 kilometers per hour slower than his speed on his way back, and therefore it takes him 20 minutes longer. If Jason drives to his parents' house at 50 kilometers per hour, how many minutes does he spend on his way back from his parents' house?
A. 60
B. 80
C. 100
D. 120
E. 150
A. 60
B. 80
C. 100
D. 120
E. 150
07 May 2022, 16:28
Kudos
Bookmarks
Bunuel
Jason drives to his parents' house and back home the same way. On the way to his parents' house, his speed is 10 kilometers per hour slower than his speed on his way back, and therefore it takes him 20 minutes longer. If Jason drives to his parents' house at 50 kilometers per hour, how many minutes does he spend on his way back from his parents' house?
A. 60
B. 80
C. 100
D. 120
E. 150
A. 60
B. 80
C. 100
D. 120
E. 150
Breaking Down the Info:
We know Jason drives at 50 km/h to his parents' house and 40 km/h on the way back. Set the amount of time it took as t in minutes, and we would have:
\(50 * t = 40 * (t + 20)\)
Then \(t = 80\), so it took 80 + 20 = 100 min to get back.
Note that the units on either side do not cooperate in the equation, but this doesn't create any problems as we are using the same units on both sides.
Answer: C
07 May 2022, 21:32
Kudos
Bookmarks
Speed to: 50 mph
Therefore his speed coming home is: 60 mph
Since the distance is constant, the ratio of the speeds driven at will be inversely proportional to the time taken
Speed TO : Speed BACK = 5 : 6
Time TO : Time BACK = 6g : 5g
And we are told that it takes him 20 minutes longer to drive to his parents house
(Time TO) — (Time BACK) = 6g - 5g = g = 20
And the Time back from his parent’s house is = 5g
5(20) = 100 minutes
C 100 minutes
Posted from my mobile device
Therefore his speed coming home is: 60 mph
Since the distance is constant, the ratio of the speeds driven at will be inversely proportional to the time taken
Speed TO : Speed BACK = 5 : 6
Time TO : Time BACK = 6g : 5g
And we are told that it takes him 20 minutes longer to drive to his parents house
(Time TO) — (Time BACK) = 6g - 5g = g = 20
And the Time back from his parent’s house is = 5g
5(20) = 100 minutes
C 100 minutes
Posted from my mobile device
