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Jon invested $10000 in a certain stock exactly three years ago. The va

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New post 20 Dec 2017, 03:18
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Jon invested $10000 in a certain stock exactly three years ago. The value of the stocks increased by 10 percent during the first year, increased by 5 percent during the second year, and decreased by 10 percent during the third year. What is the value of the stocks today?

A. $12,705
B. $11,500
C. $10,500
D. $10,395
E. $10,350

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Re: Jon invested $10000 in a certain stock exactly three years ago. The va  [#permalink]

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New post 20 Dec 2017, 04:07
Price after 3 years = 10000*(110/100)*(105/100)*(90/100) = $10395
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Re: Jon invested $10000 in a certain stock exactly three years ago. The va  [#permalink]

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New post Updated on: 20 Dec 2017, 07:05
Imo D
1000*(110/100)*(105/100)*(90/100)


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Originally posted by sumit411 on 20 Dec 2017, 05:25.
Last edited by sumit411 on 20 Dec 2017, 07:05, edited 1 time in total.
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Re: Jon invested $10000 in a certain stock exactly three years ago. The va  [#permalink]

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New post 20 Dec 2017, 06:35
Bunuel wrote:
Jon invested $10000 in a certain stock exactly three years ago. The value of the stocks increased by 10 percent during the first year, increased by 5 percent during the second year, and decreased by 10 percent during the third year. What is the value of the stocks today?

A. $12,705
B. $11,500
C. $10,500
D. $10,395
E. $10,350


The value of the stock is: \(10,000*(1.10)*(1.05)*(1-0.10)=10,395\)

(D) is the answer.
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Re: Jon invested $10000 in a certain stock exactly three years ago. The va   [#permalink] 20 Dec 2017, 06:35
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