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26 Dec 2019, 02:07
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (02:44) correct
28%
(03:08)
wrong
based on 46
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Not Attempted Yet
Joseph bought nails for $0.01 each, hooks for $0.02 each, and screws for $0.03 each. He bought a total of 18 items and paid a total of $0.32. If he bought twice as many nails as screws, how many hooks did he buy?
(A) 4
(B) 6
(C) 7
(D) 8
(e) 10
26 Dec 2019, 09:19
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Nail = n x $0.01 = 2s x $0.01
Hook = h x $0.02,
Screws = s x $0.03.
2s + h + s = 18 --> h=3(6-s)
So, h must be multiple of 3. The only sensible option is (B) : h=6 and consequently, s=4 and n=2s=8
Check:
*h+s+n=18 (OK!)
*8*1¢ + 6*2¢ + 4*3¢ = 32¢ (OK!)
FINAL ANSWER IS (B)
Posted from my mobile device
Hook = h x $0.02,
Screws = s x $0.03.
2s + h + s = 18 --> h=3(6-s)
So, h must be multiple of 3. The only sensible option is (B) : h=6 and consequently, s=4 and n=2s=8
Check:
*h+s+n=18 (OK!)
*8*1¢ + 6*2¢ + 4*3¢ = 32¢ (OK!)
FINAL ANSWER IS (B)
Posted from my mobile device
General Discussion
26 Dec 2019, 04:15
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given
x+y+z=18
and
x+2y+3z=32
also x=2z
we can solve for y
as z=18-y/3
so
5z+2y=32
y = 6
IMOB
Joseph bought nails for $0.01 each, hooks for $0.02 each, and screws for $0.03 each. He bought a total of 18 items and paid a total of $0.32. If he bought twice as many nails as screws, how many hooks did he buy?
(A) 4
(B) 6
(C) 7
(D) 8
(e) 10
x+y+z=18
and
x+2y+3z=32
also x=2z
we can solve for y
as z=18-y/3
so
5z+2y=32
y = 6
IMOB
Joseph bought nails for $0.01 each, hooks for $0.02 each, and screws for $0.03 each. He bought a total of 18 items and paid a total of $0.32. If he bought twice as many nails as screws, how many hooks did he buy?
(A) 4
(B) 6
(C) 7
(D) 8
(e) 10
