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# Just want to ask question, rather gain clarity.

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Joined: 13 Apr 2017
Posts: 3
Just want to ask question, rather gain clarity.  [#permalink]

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13 Apr 2017, 14:42
Registered to obtain anonymous input, clarity for upcoming litigations.
Given a 'Sequential' descriptive label of, 17 character positions; each position 's Allowable Character 'Pool' limited to: A-Z, a-z, 0-9 (62 'n' values).

For one label, 4 values and their positions are known. 1st pos = a; 4th pos = 5; 10th pos = a; 15th po= Z, (though I think this irrelevant to solve the question)
How many complete unique 'label variations' can there be with these existing values in these positions?

Considering that Order matters & Repetitive or duplicating characters is allowed (1st & 10th pos exemplifies).
Facts: Pool: as Set 'n' = 62 ::
Ordered SubSet as 'x'= 13
[17 total - 4 known values leaves 13 positions left open]
Calculative Formula:: n^x // 62^13

Neither Combination nor Permutation? Nor complicated. Yeilded results May be 'listed' by filling ing vacancies from left to right in order.
This seems too easy to me, others want to twist it up in details & 'encourage' others to do same.

Isn't it obvious that the more 'known' values/locations the closer to Probable match to any one specific label?
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Re: Just want to ask question, rather gain clarity.  [#permalink]

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18 Apr 2017, 23:01
TauriDragon wrote:
Registered to obtain anonymous input, clarity for upcoming litigations.
Given a 'Sequential' descriptive label of, 17 character positions; each position 's Allowable Character 'Pool' limited to: A-Z, a-z, 0-9 (62 'n' values).

For one label, 4 values and their positions are known. 1st pos = a; 4th pos = 5; 10th pos = a; 15th po= Z, (though I think this irrelevant to solve the question)
How many complete unique 'label variations' can there be with these existing values in these positions?

Considering that Order matters & Repetitive or duplicating characters is allowed (1st & 10th pos exemplifies).
Facts: Pool: as Set 'n' = 62 ::
Ordered SubSet as 'x'= 13
[17 total - 4 known values leaves 13 positions left open]
Calculative Formula:: n^x // 62^13

Neither Combination nor Permutation? Nor complicated. Yeilded results May be 'listed' by filling ing vacancies from left to right in order.
This seems too easy to me, others want to twist it up in details & 'encourage' others to do same.

Isn't it obvious that the more 'known' values/locations the closer to Probable match to any one specific label?

The area of this question is a repeated permutation.
The number of combinations is $$m^n$$, where $$m$$ is the number of choices and $$n$$ is the number of times to choose.

Generally speaking, since you understand a principle of repeated permutations, you feel this question is easy.
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Re: Just want to ask question, rather gain clarity.   [#permalink] 18 Apr 2017, 23:01
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# Just want to ask question, rather gain clarity.

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