Let <x, y, z> denote 2x + yz. Moreover, let x + y = 2p, y + z = 2q, z

From the question stem, we can estimate that this is a cyclic expression. A cyclic expression is where the order of the terms follow a cyclic pattern. This can be understood better when we break down the question stem.

It’s given that <x,y,z> = 2x + yz. In layman terms, this means, whatever the first number is has to be multiplied by 2 and added to the product of the other two numbers.

Using this, we get <x,3y,z> = 2x + 3yz = 2x + 3b {because yz = b}. Let this be equation 1.

<y,3z,x> = 2y + 3zx = 2y + 3c { notice how the positions of the variables have shifted by one place to the left and that is why I preferred to call them cyclic}. Let this be equation 2.

<z,3x,y> = 2z + 3xy = 2z + 3a. {notice how the last terms are 3b, 3c and 3a, which are cyclic as well}. Let this be equation 3

Adding the three equations, we have,
<x,3y,z> + <y,3z,x> + <z,3x,y> = 2x + 2y + 2z + 3(a+b+c). Let’s call this equation 4.

We also know that x + y = 2p, y + z = 2q, z + x = 2r; adding the equations, we get,
2x + 2y + 2z = 2(p+q+r). Substituting this value in equation 4, we obtain our required answer as 2(p+q+r) + 3(a+b+c).

The correct answer option is D.
Hope that helps!