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Manager  Joined: 08 Dec 2012
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List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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Question Stats: 58% (00:45) correct 42% (00:51) wrong based on 320 sessions

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List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

A. 5
B. 6
C. 7
D. 11
E. 12
Math Expert V
Joined: 02 Sep 2009
Posts: 55757
Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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nave81 wrote:
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

A. 5
B. 6
C. 7
D. 11
E. 12

Since -4 is the least integer in list K, then 7 is the largest integer in that list. Thus the range of the positive integers in the list is 7-1=6.

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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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Bunnel , I didn't understand when the largest positive integer in the list is 7 , how did the range become 7-1 = 6 , shouldn't it be 7
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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chaitanyas wrote:
Bunnel , I didn't understand when the largest positive integer in the list is 7 , how did the range become 7-1 = 6 , shouldn't it be 7

No, the positive integers within the list are {1,2,3,4,5,7} for which the range is 7 - 1 = 6
Intern  Joined: 20 Feb 2013
Posts: 20
Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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nave81 wrote:
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

A. 5
B. 6
C. 7
D. 11
E. 12

Solution:

Set K = ( -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7)
Range is defined as the highest value of f(x) and the lowest value of f(x). Over here the range will be 7 - (-4) = 11.

Try making a graph of the set K and see what is the difference between the maximum value and the minimum value.
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Pushpinder Gill
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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chaitanyas wrote:
Bunnel , I didn't understand when the largest positive integer in the list is 7 , how did the range become 7-1 = 6 , shouldn't it be 7

Pushpinder wrote:
Solution:

Set K = ( -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7)
Range is defined as the highest value of f(x) and the lowest value of f(x). Over here the range will be 7 - (-4) = 11.

Try making a graph of the set K and see what is the difference between the maximum value and the minimum value.

The set is {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7}. The question asks to find the range of the POSITIVE integers in the list.

The range of the POSITIVE integers in the list is {largest} - {smallest} = 7 - 1 = 6.

Hope it's clear.
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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Oh! I misread the positive numbers.
Then the range is 7 - 1 = 6
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Pushpinder Gill
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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my god. cheating.

I want to follow this question.
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Re: List K consists of 12 consecutive integers...  [#permalink]

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1
anchitg wrote:
List K consists of 12 consecutive integers, if -4 is the least integer in the list K, what is the range of the positive integers in list K?

5
6
7
11
12

k={-4,-3,-2,-1,0,1,2,3,4,5,6,7}

positive integers in the list k={1,2,3,4,5,6,7}
range=(7-1)=6

Ans B...hope it helps
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Re: List K consists of 12 consecutive integers...  [#permalink]

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1
anchitg wrote:
List K consists of 12 consecutive integers, if -4 is the least integer in the list K, what is the range of the positive integers in list K?

5
6
7
11
12

Simple one. However, the only thing to notice in this question is "range of the positive integers". You miss this and you are gone _________________
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Intern  Joined: 23 Oct 2012
Posts: 23
Re: List K consists of 12 consecutive integers. ...  [#permalink]

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audiogal101 wrote:
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K ?

(A) 5
(B) 6
(C) 7
(D) 11
(E) 12

Can someone explain how to arrive at the OA? I am getting range of 11!!

OMG!! totally need to pay attention to what Q is asking...yes...the OA is correct!
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Re: List K consists of 12 consecutive integers.  [#permalink]

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subhrm wrote:
List K consists of 12 consecutive integers. If -4 is the least integer in the list K , what is the range of positive integers in list K ?

A- 5
B- 6
C- 7
D- 11
E 12

numbers are -4,-3,-2,-1,0,1,2,3,4,5,6,7

range of positive numbers = 7-1= 6

note: zero is neither positive nor negative. it is neutral.
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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If least = -4, then largest = 7

Range = 7 - 1 = 6
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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so if it asks you for the positive and negative range then it would be 11 right? 7- (-4)= 11? or do you get two answers one for positive and one for negative?
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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Letsdothis12 wrote:
so if it asks you for the positive and negative range then it would be 11 right? 7- (-4)= 11? or do you get two answers one for positive and one for negative?

The set is {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7}.

The range of the POSITIVE integers in the list is {largest} - {smallest} = 7 - 1 = 6.
The range of the NEGATIVE integers in the list is {largest} - {smallest} = -1 - (-4) = 3.

The range of the whole set is {largest} - {smallest} = 7 - (-4) = 11.
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List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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Quote:
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

Is not this an arithmetic progression with common difference as 1?

nth term in given by $$a_n$$ = $$a_1$$ + (n-1) d
We are given that $$a_1$$= -4 and hence we can solve for a_12 and n=12
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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Top Contributor

Quote:
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

Is not this an arithmetic progression with common difference as 1?

nth term in given by $$a_n$$ = $$a_1$$ + (n-1) d
We are given that $$a_1$$= -4 and hence we can solve for a_12 and n=12

Perfectly valid approach!

Cheers,
Brent
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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Hoping for Clarification

Definition of Range?

Russian Roulette says the answer can be A B C D E anything - but reality?
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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DebbieChats wrote:
Hoping for Clarification

Definition of Range?

Russian Roulette says the answer can be A B C D E anything - but reality?

For any given set of elements/numbers, range is the distance between the largest and the smallest number on the number line.

Set {-2, 3, 5} Range= 5-(-2)=7
Set {2, 6, 1} Range= 6-1=5

step 1. arrange in ascending order
step 2. Range= (max element) - (min element)
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Re: List K consists of 12 consecutive integers. If -4 is the  [#permalink]

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What is the answer then for above? Re: List K consists of 12 consecutive integers. If -4 is the   [#permalink] 24 May 2019, 00:34
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