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List K consists of 12 consecutive integers. If 4 is the least integer
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24 Feb 2013, 12:39
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List K consists of 12 consecutive integers. If 4 is the least integer in list K, what is the range of the positive integers in list K? A. 5 B. 6 C. 7 D. 11 E. 12
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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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26 Feb 2013, 03:07
chaitanyas wrote: Bunnel , I didn't understand when the largest positive integer in the list is 7 , how did the range become 71 = 6 , shouldn't it be 7 Pushpinder wrote: Solution:
Set K = ( 4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 7) Range is defined as the highest value of f(x) and the lowest value of f(x). Over here the range will be 7  (4) = 11.
Try making a graph of the set K and see what is the difference between the maximum value and the minimum value. The set is {4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 7}. The question asks to find the range of the POSITIVE integers in the list. The range of the POSITIVE integers in the list is {largest}  {smallest} = 7  1 = 6. Hope it's clear.
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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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24 Feb 2013, 12:54
nave81 wrote: List K consists of 12 consecutive integers. If 4 is the least integer in list K, what is the range of the positive integers in list K?
A. 5 B. 6 C. 7 D. 11 E. 12 Since 4 is the least integer in list K, then 7 is the largest integer in that list. Thus the range of the positive integers in the list is 71=6. Answer: B.
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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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25 Feb 2013, 20:38
Bunnel , I didn't understand when the largest positive integer in the list is 7 , how did the range become 71 = 6 , shouldn't it be 7



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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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25 Feb 2013, 21:23
nave81 wrote: List K consists of 12 consecutive integers. If 4 is the least integer in list K, what is the range of the positive integers in list K?
A. 5 B. 6 C. 7 D. 11 E. 12 Solution: Set K = ( 4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 7) Range is defined as the highest value of f(x) and the lowest value of f(x). Over here the range will be 7  (4) = 11. Try making a graph of the set K and see what is the difference between the maximum value and the minimum value.
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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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25 Sep 2013, 07:36
anchitg wrote: List K consists of 12 consecutive integers, if 4 is the least integer in the list K, what is the range of the positive integers in list K?
5 6 7 11 12 k={4,3,2,1,0,1,2,3,4,5,6,7} positive integers in the list k={1,2,3,4,5,6,7} range=(71)=6 Ans B...hope it helps



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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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25 Sep 2013, 08:24
anchitg wrote: List K consists of 12 consecutive integers, if 4 is the least integer in the list K, what is the range of the positive integers in list K?
5 6 7 11 12 Simple one. However, the only thing to notice in this question is " range of the positive integers". You miss this and you are gone



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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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15 Jul 2014, 00:40
subhrm wrote: List K consists of 12 consecutive integers. If 4 is the least integer in the list K , what is the range of positive integers in list K ?
Answer Options:
A 5 B 6 C 7 D 11 E 12 numbers are 4,3,2,1,0,1,2,3,4,5,6,7 range of positive numbers = 71= 6 note: zero is neither positive nor negative. it is neutral.



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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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04 Dec 2016, 14:00
so if it asks you for the positive and negative range then it would be 11 right? 7 (4)= 11? or do you get two answers one for positive and one for negative?



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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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05 Dec 2016, 01:35
Letsdothis12 wrote: so if it asks you for the positive and negative range then it would be 11 right? 7 (4)= 11? or do you get two answers one for positive and one for negative? The set is {4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 7}. The range of the POSITIVE integers in the list is {largest}  {smallest} = 7  1 = 6. The range of the NEGATIVE integers in the list is {largest}  {smallest} = 1  (4) = 3. The range of the whole set is {largest}  {smallest} = 7  (4) = 11.
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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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22 May 2019, 21:07
Bunuel chetan2u VeritasKarishma GMATPrepNowQuote: List K consists of 12 consecutive integers. If 4 is the least integer in list K, what is the range of the positive integers in list K? Is not this an arithmetic progression with common difference as 1? nth term in given by \(a_n\) = \(a_1\) + (n1) d We are given that \(a_1\)= 4 and hence we can solve for a_12 and n=12
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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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23 May 2019, 08:00
adkikani wrote: Bunuel chetan2u VeritasKarishma GMATPrepNowQuote: List K consists of 12 consecutive integers. If 4 is the least integer in list K, what is the range of the positive integers in list K? Is not this an arithmetic progression with common difference as 1? nth term in given by \(a_n\) = \(a_1\) + (n1) d We are given that \(a_1\)= 4 and hence we can solve for a_12 and n=12 Perfectly valid approach! Cheers, Brent
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Re: List K consists of 12 consecutive integers. If 4 is the least integer
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21 Nov 2019, 08:36
This is so cheeky from GMAT.
The question asks what is the range of positive integers, not the range of the set. so, answer is 71 = 6 not 7(4)=11




Re: List K consists of 12 consecutive integers. If 4 is the least integer
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