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16 Sep 2014, 00:34
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E
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Difficulty:
65%
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Question Stats:
61% (02:25) correct
39%
(02:41)
wrong
based on 676
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A welder needs to construct a closed cube-shaped tank with a volume of 1 million liters. If the welder has access to only 4x2 meter sheets of metal that can be cut, and 1 cubic meter is equivalent to 1,000 liters, how many sheets of metal will be required to construct the tank?
A. 92
B. 90
C. 82
D. 78
E. 75
A. 92
B. 90
C. 82
D. 78
E. 75
16 Sep 2014, 00:34
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Bookmarks
Official Solution:
A welder needs to construct a closed cube-shaped tank with a volume of 1 million liters. If the welder has access to only 4x2 meter sheets of metal that can be cut, and 1 cubic meter is equivalent to 1,000 liters, how many sheets of metal will be required to construct the tank?
A. 92
B. 90
C. 82
D. 78
E. 75
Since 1 cubic meter = 1,000 liters, then 1 million liter tank \(= \frac{1,000,000}{1,000} = 1,000\) cubic meter tank.
\(1,000\) cubic meter tank, means that each side of the cube-shaped tank is 10 meters long (since 10^3 = 1,000).
The surface area of this tank would be \(\text{ (number of faces of a cube)} *\text{ (area of each face)} =6*10^2= 600\) square meters.
Since each sheet is \(4*2=8\) square meters, then to cover 600 square meters of area, \(\frac{600}{8}=75\) sheets will be needed.
Note that this is not a Geometry question. While it uses basic knowledge of figures, it is a Word Problem question. There are 8 questions within GMAT Prep Focus Edition that use similar principles. Here is one example.
Answer: E
A welder needs to construct a closed cube-shaped tank with a volume of 1 million liters. If the welder has access to only 4x2 meter sheets of metal that can be cut, and 1 cubic meter is equivalent to 1,000 liters, how many sheets of metal will be required to construct the tank?
A. 92
B. 90
C. 82
D. 78
E. 75
Since 1 cubic meter = 1,000 liters, then 1 million liter tank \(= \frac{1,000,000}{1,000} = 1,000\) cubic meter tank.
\(1,000\) cubic meter tank, means that each side of the cube-shaped tank is 10 meters long (since 10^3 = 1,000).
The surface area of this tank would be \(\text{ (number of faces of a cube)} *\text{ (area of each face)} =6*10^2= 600\) square meters.
Since each sheet is \(4*2=8\) square meters, then to cover 600 square meters of area, \(\frac{600}{8}=75\) sheets will be needed.
Note that this is not a Geometry question. While it uses basic knowledge of figures, it is a Word Problem question. There are 8 questions within GMAT Prep Focus Edition that use similar principles. Here is one example.
Answer: E
General Discussion
26 Dec 2015, 23:03
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Bookmarks
Hello,
Well the explanation is clear and concise.
I attempted the question with a 3D structure in mind.
Firstly we have a side of cube: 10 m
Secondly now how you could arrange 4 X 2 sheets in a 10 m side.
Interestingly if you draw the sheets in 10 X 10 side, you would only be able to put 12 such sheets in it with area of 2 X 2 remaining (I would try to draw it some other time): 12 X 6 = 72 sheets
Now as there are six sheets (in total) for the cube, so a total of 3 more sheets required to join adjacent sides.
This method took a little bit time to apply.
Thx
Well the explanation is clear and concise.
I attempted the question with a 3D structure in mind.
Firstly we have a side of cube: 10 m
Secondly now how you could arrange 4 X 2 sheets in a 10 m side.
Interestingly if you draw the sheets in 10 X 10 side, you would only be able to put 12 such sheets in it with area of 2 X 2 remaining (I would try to draw it some other time): 12 X 6 = 72 sheets
Now as there are six sheets (in total) for the cube, so a total of 3 more sheets required to join adjacent sides.
This method took a little bit time to apply.
Thx
