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Thank you=)

But I still got a question. Is it ok to use this formula if we know that machines finish different parts of work(A-1/4 of all work, B-1/6...etc)...I thought we can use it only if we know that machines A,B,C finish whole work with different rates.
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Thank you=)

But I still got a question. Is it ok to use this formula if we know that machines finish different parts of work(A-1/4 of all work, B-1/6...etc)...I thought we can use it only if we know that machines A,B,C finish whole work with different rates.

If we are given that A can do 1/4 of the job in say 4 hours and B can do 1/6 of the same job in 2 hours then A can do the whole job in 4*4=16 hours and B can do the whole job in 6*2=12 hours so 1/16+1/12=1/T.

Or as the formula for multiple entities: \(\frac{1}{t_1}+\frac{1}{t_2}+\frac{1}{t_3}+...+\frac{1}{t_n}=\frac{1}{T}\) basically represents the sum of the rates of these entities (as rate is reciprocal of time and we can add the rates of the entities to get combined rate) then the rate of A would be rate=job/time=(1/4)/4=1/16 and the rate of B would be rate=job/time=(1/6)/2=1/12 --> 1/16+1/12=1/T.

Check the link in my previous post for more.
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Bunuel, can you please explain me something.
machine A in one hour make 1/4 of the work
machine B in one hour make 1/2 of the work
machine C in one hour make 1/8 of the work
so in the first hour of work the machines together made 7/8 of the work.
Means - we need to finish 1/8 of the work. why it will be wrong to say that we need one hour + 1/8 hour to finish the work with all the 3 machines?
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Bunuel, can you please explain me something.
machine A in one hour make 1/4 of the work
machine B in one hour make 1/2 of the work
machine C in one hour make 1/8 of the work
so in the first hour of work the machines together made 7/8 of the work.
Means - we need to finish 1/8 of the work. why it will be wrong to say that we need one hour + 1/8 hour to finish the work with all the 3 machines?

Everything is correct till the red part: yes, in 1 hour three machines together can do 7/8 of the job and 1/8 of the job is to be done, which means that 7 parts out of 8 are done and 1 part is to be done, so 1/7th of what is already done is to be done. Three machines will need 1/7th of an hour more to finish the whole job --> 1 hour +1/7 hours = 8/7 hours, the same result as above.

Of course this can be done much simpler: 7/8 job/hour --> whole job in 1/(7/8)=8/7 hours (time is reciprocal of rate).
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Ye, i got it. thanks for the explanation. have a great day. +1
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Machine A can finish of a work in 4 hours, while В can finish of the work in 2 hours, and С can finish of the work in 8 hours. How many hours will it take for A, B, and С together to finish the work?
(A)
(B)
(C)
(D)
(E)

"R" stands for rate

R(A) = 1/4

R(B) = 1/2

R(C) = 1/8

Combined rate = 1/4+1/2+1/8 = 7/8

Time = 8/7 hrs
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provide options for this problem please :)

Posted from my mobile device
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provide options for this problem please :)

Posted from my mobile device

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Added the options. Thank you!
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