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04 Aug 2022, 14:44
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Guys can you help me out?
Manhattan GMAT Strategy (Guide 2 : Algebra) sometimes assumes a < or > sign as </= or >/= sign.
Is this the norm? I'm not that familiar with this.
When it comes to DS questions, it makes or breaks my answers because of this.
I'm copy pasting an exact question and their solution. Kindly enlighten me if I need to understand something here:
1. If y > 0, what is the value of y?
(1) y2 < y
(2) y is an integer.
-----------------------------------------
The question stem allows any positive values for y, including fractions.
The second statement is considerably easier than the first, so you might choose to start there.
(2) INSUFFICIENT: The statement indicates that y is an integer. The value of y could be 1, 2, 14, 192, or any other positive integer.
(1) INSUFFICIENT: What numbers make y2 ≤ y true? ----------------------- How did they assume the change in the inequality sign?
Case 1: If y = 1, then 1 ≤ 1. Therefore, 1 is a possible value for y.
Case 2: If y=1/2, then 1/4 ≤ 1/2. Therefore, 1/2 is a possible value for y.
There are at least two possible values for y.
(1) AND (2) SUFFICIENT: Together, the two statements eliminate the fraction case y=1/2, but y = 1 is still a valid case.
In order for y2≤ y to be true, y must equal 0, 1, or a fraction between 0 and 1. If y is a positive integer, then it cannot
be 0 or a fraction. The two statements together, then, are sufficient to answer the question: the value of y is 1.
The correct answer is (C)
Given my understanding, I would have taken a < as a < and marked E. Is this correct or did Manhattan just print the question wrong? PS - there are other problems where they make the same "assumption".
Kindly help me out comrades.
Manhattan GMAT Strategy (Guide 2 : Algebra) sometimes assumes a < or > sign as </= or >/= sign.
Is this the norm? I'm not that familiar with this.
When it comes to DS questions, it makes or breaks my answers because of this.
I'm copy pasting an exact question and their solution. Kindly enlighten me if I need to understand something here:
1. If y > 0, what is the value of y?
(1) y2 < y
(2) y is an integer.
-----------------------------------------
The question stem allows any positive values for y, including fractions.
The second statement is considerably easier than the first, so you might choose to start there.
(2) INSUFFICIENT: The statement indicates that y is an integer. The value of y could be 1, 2, 14, 192, or any other positive integer.
(1) INSUFFICIENT: What numbers make y2 ≤ y true? ----------------------- How did they assume the change in the inequality sign?
Case 1: If y = 1, then 1 ≤ 1. Therefore, 1 is a possible value for y.
Case 2: If y=1/2, then 1/4 ≤ 1/2. Therefore, 1/2 is a possible value for y.
There are at least two possible values for y.
(1) AND (2) SUFFICIENT: Together, the two statements eliminate the fraction case y=1/2, but y = 1 is still a valid case.
In order for y2≤ y to be true, y must equal 0, 1, or a fraction between 0 and 1. If y is a positive integer, then it cannot
be 0 or a fraction. The two statements together, then, are sufficient to answer the question: the value of y is 1.
The correct answer is (C)
Given my understanding, I would have taken a < as a < and marked E. Is this correct or did Manhattan just print the question wrong? PS - there are other problems where they make the same "assumption".
Kindly help me out comrades.
04 Aug 2022, 16:09
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Bookmarks
Hi. Happy to take a look.
For anyone interested, this is a question on page 151 in the latest 7the edition Manhattan Quant guide.
6th edition has it on page 149 and it looks the same.
In my version of the guide it says less than or equals in the set up of the question.
What edition are you using?
Posted from my mobile device
For anyone interested, this is a question on page 151 in the latest 7the edition Manhattan Quant guide.
6th edition has it on page 149 and it looks the same.
In my version of the guide it says less than or equals in the set up of the question.
What edition are you using?
Posted from my mobile device
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242CF553-00FC-4F14-AE52-FD73EE942A3D.jpeg [ 57.73 KiB | Viewed 601 times ]
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04 Aug 2022, 16:40
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Thank you for BB.
Looks like an outdated version and they have corrected it.
Posted from my mobile device
Looks like an outdated version and they have corrected it.
Posted from my mobile device
