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07 Aug 2017, 10:21
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A merchant sells three different sizes of canned tomatoes. A large can costs as much as 5 medium cans or 7 small cans. If a customer buys an equal number of small and large cans of tomatoes for the exact amount of money that would buy 200 medium cans, how many small cans will she buy?
I couldn't do this math. Can you solve this math in proper way?
I couldn't do this math. Can you solve this math in proper way?
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07 Aug 2017, 10:55
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Welcome to GMAT Club.
This question has a few issues before it can be a GMAT question. You would need to have answer choices and to provide the source of the question. As to the solution, a good-old algebra approach (L=5M and L=7S) is theonly best option that's available based on the information you provided. However, if you had answer choices, you would likely be able to backsolve the question faster.
This question has a few issues before it can be a GMAT question. You would need to have answer choices and to provide the source of the question. As to the solution, a good-old algebra approach (L=5M and L=7S) is the
07 Aug 2017, 11:28
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Hi asifprome
See below solution-
L=5M=7S-------(i)
Let he bought N number of small and N number of large cans-
N*L+N*S=200M-------(ii)
Now from (i)
5M=7S
M=7S/5
so-
200M=200*7S/5
200M=40*7S
put this value in (ii)
N*L+N*S=40*7S
Now L=7S from (i)
put this value in above equation N*L+N*S=40*7S-
N*7S+N*S=40*7S
7N+N=40*7
N=35
that means he baught 35 small Cans of tomatos
See below solution-
L=5M=7S-------(i)
Let he bought N number of small and N number of large cans-
N*L+N*S=200M-------(ii)
Now from (i)
5M=7S
M=7S/5
so-
200M=200*7S/5
200M=40*7S
put this value in (ii)
N*L+N*S=40*7S
Now L=7S from (i)
put this value in above equation N*L+N*S=40*7S-
N*7S+N*S=40*7S
7N+N=40*7
N=35
that means he baught 35 small Cans of tomatos
