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Maths3

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10 Aug 2003, 10:02
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I have forgotton basic Maths.

Could anyone enlighten on the formula for nth term
as attached?

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10 Aug 2003, 18:38
Don't use a formula. Look at what a2 and a3 are. Maybe a4. Generalize for n.
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AkamaiBrah
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18 Aug 2003, 09:24
I remember I did it in "Sec. 3" when I was 15 years.
I had not done this arithmetic maths since then.

If n = 1, a2 = a1+4 = 5
If n = 2. a3 = a2+4 = 9
If n = 3, a4 = a3+4 = 13
If n = n, an+1 = an+4 = ?

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18 Aug 2003, 10:00
looks like (4n - 3) to me.
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18 Aug 2003, 13:13
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18 Aug 2003, 15:28

Here is the solution

Arithematic Progression
an=a+(n-1)d

Here a=1 and d=4 substitute the values in the equation to get the answer which is 4n-3
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20 Jan 2004, 22:48
I believe it should be 4n+1
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21 Jan 2004, 04:23
a1=1, a2=5, a3=9,........ so an= 4n-3
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21 Jan 2004, 06:37
It should be 4n-3

if n = 0 then 4n+1 yeilds 1 which is incorrect
if n = 1 then 4n-3 yeilds 1
21 Jan 2004, 06:37
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