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Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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06 Jun 2016, 03:18
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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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06 Jun 2016, 06:00
After the 1st hour, Maxwell has travelled 4 Km. And Brad just left home. So the distance between them = 54  4 = 50. Relative speed = 4 +6 = 10 Kmph. Now to cover these 50 Kms, they will take 50/10 = 5 Hrs. So in 5 hrs, Maxwell walks 5*4 = 20 Kms. So total distance travelled by Maxwell = 4 + 20 = 24. Hence D.



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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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06 Jun 2016, 06:49
d = 54 km rM = 4 km/h rB = 6 km/h We know that if two people started walking towards at the same time, the time travelled at the time of meeting each other is the same. In this case, Maxwell leaves 1 hour earlier. Then, if tM = x, then tB = x 1 We know that at the time M & B meet, they would have together travelled the total distance: Total distance = tM * rM + tB * rB = 54 x * 4 + (x1) * 6 = 54 4x + 6x  6 = 54 10x = 60 x = 10
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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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07 Jun 2016, 00:14
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Total Distance = 54 kms Maxwell Speed = 4 kms/hr Maxwell traveled for 1hour before Brad started , therefore Maxwell traveled for 4 kms in 1 hour. Time taken = Total Distance / Relative Speed Total Distance after Brad started = 50 kms Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4 = 10 kms/hr Time taken = 50 / 10 = 5 hrs Distance traveled by Maxwell = Maxwell's speed * time taken = 4 * 5 = 20+4 = 24 kms... Answer  D Please, consider giving kudos if you find my answer helpful in any way



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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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07 Jun 2016, 00:35
Bunuel wrote: Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 54 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the distance traveled by Maxwell?
(A) 16 (B) 18 (C) 20 (D) 24 (E) 30 I understand question as: the diatance travelled by Maxwell when both of them meet. In the first hour Maxwell walks: (4km/h) * 1 hr = 4 KmNow the distance between Maxwell and Brad is 544 = 50 Km Both are moving towards each other. Relative Speed = 6+ 4 = 10 Km/h They will cross each other at (50/10) hours = 5 hours. Maxwell walked for these 5 hours = 5 * 4 = 20 Km.Total distance = 20+ 4 = 24 Km D is the option.



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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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07 Jun 2016, 02:43
Bunuel wrote: Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 54 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the distance traveled by Maxwell?
(A) 16 (B) 18 (C) 20 (D) 24 (E) 30 Brad Started his travel I hour later,so their distance remains after 1 hour =(544)=50 they run 50 km with their individual to meet each other. So,Each answer choice subtracted by 4 ,indicates Maxwell's traveled distance of 50 km and the rest of the distance traveled must be matched with Brad's traveled distance. Only Answer Choice D matched this criteria. Maxwell's total travel distance =24,Contribution towards travelling distance of Maxwell=244=20,Remained 30km (5020) is Brad'd traveled distance ,since it is only divisible by Brad's speed(6km/h) Correct answer D
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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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07 Jun 2016, 07:21
Bunuel wrote: Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 54 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the distance traveled by Maxwell?
(A) 16 (B) 18 (C) 20 (D) 24 (E) 30 I believe that the question should mention 'what is the distance travelled by Maxwell when they both met' Maxwell travelled 4 Kms for 1 hr while brad was not moving. Remaining distance= 50 Relative speed= 4+6= 10 Time travelled to meet each other= 50/10= 5hrs Maxwell travelled total for 5 hrs or 20 kms + 4 kms = 24 kms D is the answer
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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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07 Aug 2017, 10:10
Bunuel wrote: Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 54 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the distance traveled by Maxwell?
(A) 16 (B) 18 (C) 20 (D) 24 (E) 30 (544)/(4+6)=5 hrs 5*4+4=24 miles for M



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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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07 Aug 2017, 14:23
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I think the question must be reworded: what distance did Maxwell walk by the time he met with...



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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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09 Aug 2017, 13:32
mvictor wrote: I think the question must be reworded: what distance did Maxwell walk by the time he met with... Yeah the question should be reworded. It should specify the point in time for which we are measuring. Maxwell can possibly keep walking for all of the 54 km. The question doesn't specify where to stop so technically he could walk any measure of the distance between 454.



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Re: Maxwell leaves his home and walks toward Brad's house. One hour later, [#permalink]
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10 Aug 2017, 09:33
Bunuel wrote: Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 54 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the distance traveled by Maxwell?
(A) 16 (B) 18 (C) 20 (D) 24 (E) 30 We can let Brad’s time = t, and thus Maxwell’s time = t + 1. Furthermore, since distance = rate x time, Brad’s distance = 6t and Maxwell’s distance = 4(t + 1). Since their total distance is 54 km, we can create the following equation: Brad’s distance + Maxwell’s distance = 54 6t + 4(t + 1) = 54 6t + 4t + 4 = 54 10t = 50 t = 5 Thus, Maxwell has traveled 4(5 + 1) = 24 km when they meet. Answer: D
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Re: Maxwell leaves his home and walks toward Brad's house. One hour later,
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