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Of the 100 passengers who entered a railroad station, 10 passengers ha

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Of the 100 passengers who entered a railroad station, 10 passengers ha  [#permalink]

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14 Oct 2019, 07:40
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Difficulty:

15% (low)

Question Stats:

100% (00:53) correct 0% (00:00) wrong based on 17 sessions

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Of the 100 passengers who entered a railroad station, 10 passengers had 4 pieces of luggage each, 20 had 5 pieces of luggage each, 50 had 2 pieces of luggage each, and the rest had no luggage. What was the average (arithmetic mean) number of pieces of luggage per passenger?

A. 1
B. 1.4
C. 2
D. 2.4
E. 3

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Re: Of the 100 passengers who entered a railroad station, 10 passengers ha  [#permalink]

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14 Oct 2019, 10:04
Bunuel wrote:
Of the 100 passengers who entered a railroad station, 10 passengers had 4 pieces of luggage each, 20 had 5 pieces of luggage each, 50 had 2 pieces of luggage each, and the rest had no luggage. What was the average (arithmetic mean) number of pieces of luggage per passenger?

A. 1
B. 1.4
C. 2
D. 2.4
E. 3

total luggage ; 40+100+100 ; 240
avg ; 240/100 ; 2.4
IMO D
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Re: Of the 100 passengers who entered a railroad station, 10 passengers ha  [#permalink]

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14 Oct 2019, 10:40
Bunuel wrote:
Of the 100 passengers who entered a railroad station, 10 passengers had 4 pieces of luggage each, 20 had 5 pieces of luggage each, 50 had 2 pieces of luggage each, and the rest had no luggage. What was the average (arithmetic mean) number of pieces of luggage per passenger?

A. 1
B. 1.4
C. 2
D. 2.4
E. 3

Total number of passengers = 100.

we have:

1. 10 Passengers with 4 pieces of luggage = 10*4

similarly
2. = 20*5
3. = 50*2
4. 20 passengers do not have any luggage = 20*0

total luggage = 40+100+100+0 = 240

Average = 240/100 = 2.4 luggage per passenger.

Hence D is correct.
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Re: Of the 100 passengers who entered a railroad station, 10 passengers ha  [#permalink]

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14 Oct 2019, 10:51
Bunuel wrote:
Of the 100 passengers who entered a railroad station, 10 passengers had 4 pieces of luggage each, 20 had 5 pieces of luggage each, 50 had 2 pieces of luggage each, and the rest had no luggage. What was the average (arithmetic mean) number of pieces of luggage per passenger?

A. 1
B. 1.4
C. 2
D. 2.4
E. 3

$$\frac{10*4 + 20*5 + 50*2}{100}$$

$$= \frac{40 + 100 + 100}{100}$$

$$= 2.40$$, Answer must be (D)
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Re: Of the 100 passengers who entered a railroad station, 10 passengers ha  [#permalink]

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14 Oct 2019, 11:36
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Of the 100 passengers who entered a railroad station, 10 passengers had 4 pieces of luggage each, 20 had 5 pieces of luggage each, 50 had 2 pieces of luggage each, and the rest had no luggage. What was the average (arithmetic mean) number of pieces of luggage per passenger?

10*4 + 20*5+ 50*2 = 240 /100 = 2.4 D is the chocie
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Re: Of the 100 passengers who entered a railroad station, 10 passengers ha   [#permalink] 14 Oct 2019, 11:36
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