Of the 100 passengers who entered a railroad station, 10 passengers ha

Question

Of the 100 passengers who entered a railroad station, 10 passengers had 4 pieces of luggage each, 20 had 5 pieces of luggage each, 50 had 2 pieces of luggage each, and the rest had no luggage. What was the average (arithmetic mean) number of pieces of luggage per passenger?

A. 1
B. 1.4
C. 2
D. 2.4
E. 3

A. 1
B. 1.4
C. 2
D. 2.4
E. 3

Archit3110 · Answer

total luggage ; 40+100+100 ; 240
avg ; 240/100 ; 2.4
IMO D

vivek920368 · Answer

Total number of passengers = 100.

we have:

1. 10 Passengers with 4 pieces of luggage = 10*4

similarly
2. = 20*5
3. = 50*2
4. 20 passengers do not have any luggage = 20*0

total luggage = 40+100+100+0 = 240

Average = 240/100 = 2.4 luggage per passenger.

Hence D is correct.

Abhishek009 · Answer

\frac{10*4 + 20*5 + 50*2}{100}

= \frac{40 + 100 + 100}{100}

= 2.40 , Answer must be (D)

daagh · Answer

Of the 100 passengers who entered a railroad station, 10 passengers had 4 pieces of luggage each, 20 had 5 pieces of luggage each, 50 had 2 pieces of luggage each, and the rest had no luggage. What was the average (arithmetic mean) number of pieces of luggage per passenger?

A. 1
B. 1.4
C. 2
D. 2.4
E. 3

10*4 + 20*5+ 50*2 = 240 /100 = 2.4 D is the chocie

Of the 100 passengers who entered a railroad station, 10 passengers ha

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Of the 100 passengers who entered a railroad station, 10 passengers ha

Prep Toolkit

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