Of the 500 temperature records, 76% are less than or equal to 153 degr

To get the median we need the avg. of \(250^{th}\) and \(251^{th} \) records.

We know \(380\) records have values \(\leq\) 153


(1) Of the records greater than \(100\) , \(60\% \) are less than of equal to \(153.\)

We do not know how many records have values greater than \(100,\) even if we knew that , we would still not know the values of \(250 \) and \(251 \) record .

INSUFF.

(2) Of the records greater than \(100\), \(40\% \) are greater than \(153.\)

We know \(120\) records have values more than \(153\)

Let \(x \) is the # of records with values more than \(100\)

\(.40x= 120 \)

\(x= 300\)

From this we know there are \(300\) records with values more than \(100\) and \(200 \) records with values \(\leq\) \(100\).

Still we cannot get the values of \(250^{th} \) and \(251^{th} \) records

INSUFF.

\(1 + 2 \)

\(380\) records \(\leq 153\)
\(200 \) records \(\leq 100\)
\(300\) records \(> 100\)

Please refer to the attached number line


So at the max. we can conclude that the \(250^{th}\) and \(251^{th}\) record will have values greater than \(100\) but less than equal to \(153\)

\(100 <\) Median \(\leq 153\)

But still we cannot get the values of \(250^{th} \) and \(251^{th}\) record to get the exact median.

Ans E