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# Over a ten-year period Pat's income rose from $15,000 to$35,000.

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Re: Over a ten-year period Pat's income rose from $15,000 to$35,000. [#permalink]
robanm90 wrote:
Over a ten-year period Pat's income rose from $15,000 to$35,000. What was the percent increase in her income?
A) 33 [1][/3]%
B) 42.8%
C) 133 [1][/3]%
D) 142.8%
E) 233 [1][/3] %

Just apply the formula

35-15/15 *100 = roughly 133

Thus
"C"
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Re: Over a ten-year period Pat's income rose from $15,000 to$35,000. [#permalink]
robanm90 wrote:
Over a ten-year period Pat's income rose from $15,000 to$35,000. What was the percent increase in her income?
A) 33 [1][/3]%
B) 42.8%
C) 133 [1][/3]%
D) 142.8%
E) 233 [1][/3] %

For faster calculation ignore the zero's (000)

$$\frac{35 - 15}{15} *100$$

= $$\frac{20}{15} *100$$

= $$133 \frac{1}{3}$$ %

Thus, the answer will be (C) $$133 \frac{1}{3}$$ %
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Re: Over a ten-year period Pat's income rose from $15,000 to$35,000. [#permalink]
robanm90 wrote:
Over a ten-year period Pat's income rose from $15,000 to$35,000. What was the percent increase in her income?
A) 33 [1][/3]%
B) 42.8%
C) 133 [1][/3]%
D) 142.8%
E) 233 [1][/3] %

We need to determine the percentage increase from 15,000 to 35,000. We use the percent increase formula: (new - old)/old x 100%:

(35,000 - 15,000)/15,000 x 100%

20,000/15,000 x 100%

4/3 x 100% = 133.3%

Re: Over a ten-year period Pat's income rose from $15,000 to$35,000. [#permalink]