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Bunuel
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P will Always be even, Q could be either odd or even.

Q(P+1) will be Even if Q is Even.

2P + 3Q will be Even if Q is Even.

P * Q^2 will Always be Even (since P is even)

P^2 * Q^3 will Always be Even (Since P is even)

Hence none of the above, so answer is E
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Even * Even = Even
Even * Odd = Even
Odd * Odd = ODD


P = Even (divisible by 4)
Q = Odd / Even (divisible by 3 . Eg 3,6,9,12....)


A. Q(P+1)

Case 1: Odd * Odd = Odd [3(4+1) => 15]
Case 2: Even * Odd = Even [6(4+1) => 20]

Insufficient.

B. 2P+3Q

2P = Always even
3Q = Odd / Even

Case 1: Odd * Odd = Odd
Case 2: Even * Odd = Even

Insufficient

C. \(P*Q^2\)
P = Even
\(Q^2\) = Odd / Even

Insufficient

D.\(P^2*Q^3\)

P = Even
\(Q^2\) = Odd / Even

Insufficient

E. None of the above. Sufficient

Therefor ans : Option E
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