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stolyar
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PARANOID EQUATION 31 Aug 2003, 00:14
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Solve the equation: (R!)!+|R|=2R
:eyes



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PARANOID EQUATION 31 Aug 2003, 02:22
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R! is only defined for R>=0, so we can rewrite the equation as
R!!+R=2R or R!!=R
solving we get R=1 and R=2
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stolyar
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PARANOID EQUATION 31 Aug 2003, 04:26
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what other people think?
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javropu
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PARANOID EQUATION 31 Aug 2003, 04:38
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ups! that doesnt sound as good as "correct" :(
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sachanta
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PARANOID EQUATION 31 Aug 2003, 10:09
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R!!+R=2R -------(1)
or
R!!-R=2R---------(2)

solving (1) gives R!!=R
and solving (2) gives R!!=3R

How can anything satisfy both these equations? Cannot think of any possible values
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camel
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PARANOID EQUATION 31 Aug 2003, 19:29
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I get the same thing as Jav.

R=1 or R=2
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Anand Kannan
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PARANOID EQUATION 02 Sep 2003, 03:06
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And hey 0!! = 0 too!!!!...So, the list of values will be 0,1,2 that will satisfy this condition.

Correct me if wrong.
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PARANOID EQUATION 02 Sep 2003, 05:48
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Anand Kannan Posted: Tue Sep 02, 2003 10:06 am Post subject:

--------------------------------------------------------------------------------

And hey 0!! = 0 too!!!!...So, the list of values will be 0,1,2 that will satisfy this condition.

Correct me if wrong.
Anand


0 Cannot be a correct answer. 0! = 1, 1!= 1 + 0 = 1 not equal to 2*0 = 0

For me answers 1 and 2



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