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sambam
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sambam
Point K = (A,0), Point G = (2A + 4, \(\sqrt{2A+ 9}\)). Is the distance between point K and G prime?

(1) \(A^2 – 5A – 6 = 0\)
(2) \(A > 2\)

Bunuel, Original Source is Manhattan Prep. Please help to edit. Thank you.

Edited. Thank you.
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Bunuel, can you please show, how you simplified

d=(2A+4−A)2+(2A+9−−−−−−√−0)2−−−−−−−−−−−−−−−−−−−−−−−−−√=(A+5)2−−−−−−−√=|A+5|d=(2A+4−A)2+(2A+9−0)2=(A+5)2=|A+5|
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Bunuel, can you please show, how you simplified

d=(2A+4−A)2+(2A+9−−−−−−√−0)2−−−−−−−−−−−−−−−−−−−−−−−−−√=(A+5)2−−−−−−−√=|A+5|d=(2A+4−A)2+(2A+9−0)2=(A+5)2=|A+5|

\(d=\sqrt{(2A+4-A)^2+(\sqrt{2A+9}-0)^2}=\sqrt{(A+4)^2+(\sqrt{2A+9})^2}=\)

\(=\sqrt{(A^2+8A+16)+(2A+9)}=\sqrt{A^2+10A+25}=\sqrt{(A+5)^2}=|A+5|\)
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