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aayushimehta12
all butler questions
problem-solving-butler-2-questions-every-day-280904.html#p2166581
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PrabhatKC
D The answe right?
Why are you saying a definite no for statement 2?

The example you mentioned in the statement 1 is itself an example for a yes answer
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D The answe right?
why no for 2nd?

i think set will be an infinite as given condition says. even if it says 4 is in the set value can go backwards as well if we assume t+1 as a 4 then t will be 3 and so on.

experts is it right?
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please help, ans is B - but I’m unable to get to it

I only got so far as to understand, it has to be a non-prime no
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If I am not wrong, In statement-2, it is possible to take out a common factor from each term between 19!+3 to 19!+19 and hence, the number will not be a prime number.
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I think in the first statement, is n >18! it can be 18!+1 or 2 or infinity. So finding a particular factor p is not possible

for statement 2, since p is between 3 and 19, which means p can be 4 or 5 till 18 which would make it an ideal factor for 19!+ any other number between 4 and 18. Thus we can conclude that p is a factor (yes) satisfied
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This is a rip of the following official question: does-the-integer-k-have-a-factor-p-such-that-1-p-k-126735.html
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thankyouu so much!
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What’s this?
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What’s this?
Question: X = ?

Statement 1: 100 = N*x
Both N and x are unknown, insufficient

Statement 2: 150 = (N+5)*(x+1)
Both N and x are unknown, insufficient

Both statements together are 2 equations, 2 variables, can be solved. Answer is C

I hope I am right.
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I think E.

final equation after combining both statements 45 = N+5x. and you will see for value N=20 and x=5 plus N=25 and x=4 from these equation satisfies with N*x = 100 and (N+5)*(x+1)

(N+5)*(x+1) = 150.
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There are two possible solutions for this, x = 4 and 5. Idk if that counts as option C or E.
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