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can any one explain please?

Discussed in detail here: a-contractor-hired-two-paving-firms-to-pave-a-parking-lot-the-first-383504.html

A contractor hired two paving firms to pave a parking lot. The first firm was to pave \(\frac{5}{8}\) of the parking lot, and the second firm was to pave the rest. On the first day, the first firm paved \(\frac{2}{3​}\) of its portion and the second firm paved \(\frac{1}{2}\) of its portion. What fraction of the parking lot was not paved on the first day?

A. \(​\frac{8}{48}​\)

B. \(\frac{​10}{48​}\)

C. \(\frac{​15}{48​}\)

D. \(\frac{​16}{48​}\)

E. \(​\frac{19}{48}\)

Say the parking lot is 48 unit^2 (we have 5/8, 2/3 and 1/2 there, so 48 = 8*3*2 might be a good number to work with, also all fractions in the options have 48 in the denominators).

The first firm was to pave \(\frac{5}{8}\) of the parking lot. So, it must pave 5/8*48 = 30 unit^2 and the second team must pave the remaining 18 unit^2.

On the first day, the first firm paved \(\frac{2}{3​}\) of its portion, so it paved 2/3*30 = 20 unit^2 and the second firm paved \(\frac{1}{2}\) of its portion, so it paved 1/2*18 = 9 unit^2.

Totally they paved 20 + 9 = 29 unit^2 and 48 - 29 = 19 unit^2 is left to pave, which is 19/48 of the parking lot.

Answer: E.

Hope it helps.

thank you that helps

Data Sufficiency Butler: June 2024
June 26	DS 1	DS 2

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Problem Solving Butler: June 2024
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Help.
Are these IQ questions asked in GMAT?

This is an arithmetic question, so yes. Plus if you’d search the question you’d find this topic:
the-product-of-the-two-digit-numbers-above-is-the-three-digit-number-168914.html

And upon examining the tags you’d discover that it’s from OG!

anyone explain plz

Yes 2 is right in this case

For the second question

where can i find the question of the day

Question of the day are posted around 14:00 IST. You can find links to "Butler" questions in this chat group. Else here is a link for PS Butler problem-solving-butler-2-questions-every-day-280904.html You can navigate to other Butlers from the same page.

Data Sufficiency Butler: June 2024
June 27	DS 1	DS 2

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Problem Solving Butler: June 2024
June 27	PS 1	PS 2

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Can anyone please solve this question? Soumya and Vivian start together from the same point in
the same direction and run around a circular race track.
They agree that every time either of them overtakes the
other, the former would give to the latter as many coins
as the latter had. But if one of them overtakes the other
at the starting point, then the latter had to give half of
what he had to the former. Soumya runs at a speed that
is  ve times the speed of Vivian. Vivian had only one coin
initially and Soumya had 182 coins at the end of the race.
How many coins could Soumya have had in the beginning?

Soumya and Vivian start together from the same point in
the same direction and run around a circular race track.
They agree that every time either of them overtakes the
other, the former would give to the latter as many coins
as the latter had. But if one of them overtakes the other
at the starting point, then the latter had to give half of
what he had to the former. Soumya runs at a speed that
is 5 times the speed of Vivian. Vivian had only one coin
initially and Soumya had 182 coins at the end of the race.
How many coins could Soumya have had in the beginning?

Let’s denote the earnings of the 8 persons as a1, a2, a3, a4, a5, a6, a7, a8.
The average earning of the group is Rs 25 per day, so the total earnings of the group is:
Sum(a1 to a8) = 8 * 25 = 200 Rs

Let’s denote the highest earning as aH and the lowest earning as aL. Given:
aH - aL = 45

When the highest and lowest earners are excluded, the average earning of the remaining 6 persons is Rs 22.5 per day. Therefore, the total earnings of the remaining 6 persons is:
Sum(a1 to a8) - aH - aL = 6 * 22.5 = 135 Rs

Using the total earnings of the group:
200 - aH - aL = 135
aH + aL = 200 - 135 = 65

We now have two equations:
1. aH - aL = 45
2. aH + aL = 65

By solving these equations simultaneously, we add them to eliminate aL:
2aH = 110
aH = 55

Substituting aH back into the second equation to find aL:
55 + aL = 65
aL = 10

The highest earning is Rs 55 and the lowest earning is Rs 10.

Next, we need to find the average earning of the group when the three persons whose sum of earnings is equal to the highest earning leave the group. Let’s denote these three persons’ earnings as ax, ay, az, and we have:
ax + ay + az = aH = 55

The total earnings of the group is Rs 200. If these three persons leave, the total earnings of the remaining 5 persons will be:
200 - 55 = 145 Rs

The average earning of the remaining 5 persons will be:
145 / 5 = 29 Rs

Thus, the average earning of the group when the three persons whose sum of earnings is equal to the person having highest earning leave the group is Rs 29.

I have posted the screenshot of this question. Can anyone please solve this question.