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arbre
Hi,
If a number less than 100 is not divisible by any prime divisor less than 10, then the number has to be prime. And, of course, the only prime divisors less than 10 are 2, 3, 5, and 7. So those are the only divisors we have to check. It's not divisible by any of those numbers, it is a prime number. So for example, here's a practice problem.

Then what about those bigger than 100, and why?

Thanks a lot in advance

Let's say the number is 101. The square root of 101 is roughly 10, so again we only need to check prime numbers less than 10. You can verify that 101 is not divisible by 2, 3, 5, and 7. Had 101 not been prime, it would have at least two prime factors. Since we know it is not divisible by 2, 3, 5, or 7, the smallest possible prime decomposition of 101 would be 11 * 11, which is already greater than 101. We know 101 cannot have a prime factor greater than 11 because that assumption would lead to a product which is even greater than 11 * 11. Similarly, 101 cannot have more than two prime factors, again we would have a product which is greater than 11 * 11. We see that the smallest possible prime decomposition of 101 is greater than 101, which means that 101 itself must be a prime number.

In general, if you know that x is not divisible by primes that are less than √x, then x itself must be prime. You can use the above reasoning to see this. If x were not prime, then it would have at least two prime factors and both of those factors would be greater than √x. Since the product of two numbers greater than √x is greater than x, x cannot have two prime factors, which means that x must be a prime number.