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ki
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I will appreciate someone's help with this question.

3^6x=8100

x=?

Thanks,
Khurram



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your writing is more than ambiguous

do you mean 3^(6x)=8100?
if yes, then x is difficult to find. It could be found via logariphming.

if you mean (3^6)x=8100, then x=100/3^2=100/9=11 and 1/9
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sudzpwc
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its (3)^6x = 8100.How can it be solved without logarthims?anybody
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ki
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It is 3^(6x) = 8100. Sorry, couldn't make the statement clear earlier.

Is there a way to sovle it without logarithms?

Thanks.
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Not really.

If you had a problem like this:

3^(6x) = 531441, you could solve as follows:

3^(6x) = (3^x)^6 = 531441 = 9^6

=> 3^x = 9

x = 2

However, the 6th root of 8100 is not a power of 3 so IMO this problem cannot be solved without logrithms or some other form of non=GMAT math.



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