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Nikhil54321
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abhimahna
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Nikhil54321
Hi Abhi,

Thanks for your reply !!!

I didn't understand these two points

In order to find multiples of 120, just take 2^3, 3 and 5 out of the powers of 7200.

[/b]So, I can say number of factors of 7200 which are multiples of 120 are 2^2 * 3^1 * 5^1


Hilighted part I didn't understand. Can you please elaborate ?

Hi Nikhil54321 ,

What I meant was in order to find the factors which are multiples of 120, just take the prime factors required to make 120 out of 7200.

So, I have three 2s , one 3 and one 5 in 120.

I will take these out of the prime factors of 7200.

Now, after taking them out you can calculate the number of factors of pending prime factors.

The final result I will get will all be the multiples of 120.

Let me know in case of further concerns.
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Nikhil54321
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Got it.. Thank you :)
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Nikhil54321
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One more doubt. How to calculate for not divisible.

Suppose 7200 is the number and factors are 2^5.3^2.5^2

number of factors divisible by 75 = 2^5.3^1 = 12

I want to calculate number of factors not divisible by 75 ?

Thanks in Advance !!!
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One more doubt. How to calculate for not divisible.

Suppose 7200 is the number and factors are 2^5.3^2.5^2

number of factors divisible by 75 = 2^5.3^1 = 12

I want to calculate number of factors not divisible by 75 ?

Thanks in Advance !!!

Hi Nikhil54321 ,

Number of factors NOT divisible by 75 = Total Factors - Number of factors divisible by 75

I hope it makes sense. :)
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Yeah bro.

You are right.

Thank you :)
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