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# Renee rides her bicycle 20 miles in m minutes. If she can ride x miles

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Renee rides her bicycle 20 miles in m minutes. If she can ride x miles [#permalink]

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08 Mar 2017, 10:17
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80% (00:46) correct 20% (00:43) wrong based on 64 sessions

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Renee rides her bicycle 20 miles in m minutes. If she can ride x miles in 10 minutes, which of the following equals x?

A. m/200
B. m/20
C. m/2
D. 2m
E. 200/m

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Magoosh GMAT Instructor
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Renee rides her bicycle 20 miles in m minutes. If she can ride x miles [#permalink]

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08 Mar 2017, 15:44
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Renee rides her bicycle 20 miles in m minutes. If she can ride x miles in 10 minutes, which of the following equals x?

A. m/200
B. m/20
C. m/2
D. 2m
E. 200/m

I'm happy to respond. This is a very basic proportion problem. See:
GMAT Quant: Rates and Ratios

$$\frac{distance}{time} = \frac{20 miles}{(m) min} = \frac{(x) miles}{10 min}$$

Units are the same on both sides, so cancel the units.

$$\frac{20}{m} = \frac{x}{10}$$

We want to solve for x, so multiply both sides by 10.

$$\frac{200}{m} = x$$

OA = (E)

Does all this make sense?
Mike
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Mike McGarry
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Joined: 05 Jan 2017
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Location: India
Re: Renee rides her bicycle 20 miles in m minutes. If she can ride x miles [#permalink]

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09 Mar 2017, 05:26
speed = 20/m
distance covered in 10 minutes = x = (20/m) x 10 = 200/m

Option E
Target Test Prep Representative
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Re: Renee rides her bicycle 20 miles in m minutes. If she can ride x miles [#permalink]

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15 Mar 2017, 16:16
Renee rides her bicycle 20 miles in m minutes. If she can ride x miles in 10 minutes, which of the following equals x?

A. m/200
B. m/20
C. m/2
D. 2m
E. 200/m

We are given that Renee’s rate is 20/m and that it’s also x/10. We can set up the proportion:

20/m = x/10

200 = mx

200/m = x

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Scott Woodbury-Stewart
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Re: Renee rides her bicycle 20 miles in m minutes. If she can ride x miles [#permalink]

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28 Mar 2017, 06:35
ScottTargetTestPrep wrote:
Renee rides her bicycle 20 miles in m minutes. If she can ride x miles in 10 minutes, which of the following equals x?

A. m/200
B. m/20
C. m/2
D. 2m
E. 200/m

We are given that Renee’s rate is 20/m and that it’s also x/10. We can set up the proportion:

20/m = x/10

200 = mx

200/m = x

Hey Scott

How do we know that we have to equate the two?

I followed unitary method and then equated after finding miles per min.

It would be great if you could explain this.
Thanks.
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 2738
Location: United States (CA)
Re: Renee rides her bicycle 20 miles in m minutes. If she can ride x miles [#permalink]

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31 Mar 2017, 06:19
Shiv2016 wrote:
ScottTargetTestPrep wrote:
Renee rides her bicycle 20 miles in m minutes. If she can ride x miles in 10 minutes, which of the following equals x?

A. m/200
B. m/20
C. m/2
D. 2m
E. 200/m

We are given that Renee’s rate is 20/m and that it’s also x/10. We can set up the proportion:

20/m = x/10

200 = mx

200/m = x

Hey Scott

How do we know that we have to equate the two?

I followed unitary method and then equated after finding miles per min.

It would be great if you could explain this.
Thanks.

Hey Shiv2016,

Great question.

We understand from the context that Renee is riding her bike at a constant rate. Since we are given that Renee rides her bike 20 miles in m minutes AND she can ride x miles in 10 minutes, we are essentially being told that the two rates are the same, and that is why we set them equal to each other.
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Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Re: Renee rides her bicycle 20 miles in m minutes. If she can ride x miles   [#permalink] 31 Mar 2017, 06:19
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