joepc
Similarly selecting 2 apples
Selecting 2 apples is one way
and not selecting 2 apples is another way, hence it is 2 ways.
Here's the first part of your error. If there are four apples in the basket, then 'selecting two apples' and 'not selecting two apples' are the same thing. (In both cases, you'll end up with two apples in your hand and two left over in the basket). Likewise, 'selecting three apples' and 'not selecting one apple' are the same thing. (You'll end up with three apples in your hand and one left in the basket.)
Quote:
Hence the total ways is 2 to the Power 4 and it is 16 ways
which is same as of selecting 4 different numbered\Weighted Apple or distinct type of apples in the basket
Getting confused here, can somebody help?
Here's the second problem. You don't multiply the cases together, you just count them! If you multiply them together, what you'd be counting is the number of ways of picking two apples, AND not picking two apples, AND picking one apple, AND not picking one apple, AND picking three apples, etc. That is,
multiplication goes with 'and'.
Instead, you just count up the cases.
Case 1: You pick 4 apples.
Case 2: You pick 3 apples.
Case 3: You pick 2 apples.
Case 4: You pick 1 apple.
Case 5: You pick no apples.
That's five cases in total.
To continue the analogy, you add, or count cases, when you have an
'or' in the problem. You want to pick either two apples, OR three apples, OR one apple, OR no apples, etc. So, you add rather than multiplying.
There are 5 cases for apples, 6 for mangoes, and 3 for kiwis.
You multiply those numbers together, because you're back with 'and' again. You're picking apples AND mangoes AND kiwis. So, 5*6*3 = 90.
But can you work out why we subtract 1 at the end?