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Suppose a train travels x miles in y hours and 15 minutes. Its average

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Suppose a train travels x miles in y hours and 15 minutes. Its average  [#permalink]

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New post Updated on: 07 Jul 2019, 01:32
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

83% (01:04) correct 17% (01:02) wrong based on 92 sessions

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Originally posted by Bunuel on 20 May 2017, 06:06.
Last edited by SajjadAhmad on 07 Jul 2019, 01:32, edited 1 time in total.
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Re: Suppose a train travels x miles in y hours and 15 minutes. Its average  [#permalink]

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New post 20 May 2017, 06:15
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Bunuel wrote:
Suppose a train travels x miles in y hours and 15 minutes. Its average speed in miles per hour is

(A) (y + 15)/x
(B) x(y − 1/4)
(C) x/(y + 1/4)
(D) x/(y + 15)
(E) (y + 1/4)/x


Average speed in miles per hour = (total distance in miles)/(total time in hours)
y hours and 15 minutes = y + 1/4 hours

So, average speed in miles per hour = x/(y + 1/4)

Answer:

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Re: Suppose a train travels x miles in y hours and 15 minutes. Its average  [#permalink]

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New post 26 Nov 2017, 12:15
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Hi All,

This question can be solved in a couple of different ways; since it makes a direct reference to the AVERAGE SPEED formula, you might find it easiest to just set up that formula and solve:

Total Distance = (Average Speed)(Total Time)

Given the information in the prompt, we have....

(X miles ) = (Average Speed)(Y + 1/4 hours)
Average Speed = (X)/(Y + 1/4)

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Re: Suppose a train travels x miles in y hours and 15 minutes. Its average  [#permalink]

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New post 19 Nov 2019, 19:19
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Bunuel wrote:
Suppose a train travels x miles in y hours and 15 minutes. Its average speed in miles per hour is

(A) (y + 15)/x
(B) x(y − 1/4)
(C) x/(y + 1/4)
(D) x/(y + 15)
(E) (y + 1/4)/x

Source: Nova GMAT
Difficulty Level: 550


The time, in hours, is y + 15/60 = y + ¼. So, the average rate is x/(y + 1/4) miles per hour.

Answer: C
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Re: Suppose a train travels x miles in y hours and 15 minutes. Its average   [#permalink] 19 Nov 2019, 19:19
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