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Let a to m be the 13 #
Subtract
a+b+c+... +m=70(13) = 910
- a+b+c+...+j = 90(10)= - 900
k+l+m= 10
Thus, the average is 10/3
B

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Bunuel
The average (arithmetic mean) of 13 numbers is 70. If the average of 10 of these numbers is 90, what is the average of the other 3 numbers?


(A) \(-130\)

(B) \(\frac{10}{3}\)

(C) \(30\)

(D) \(90\)

(E) \(290\)

Look at the deviations of the numbers from the average.

The average is 70.
10 numbers are 20 more than average so have a total deviation of +200.
The 3 numbers will make up for it with a deficit of 200/3 each i.e. their average will be 70 - 200/3 = 10/3

Answer (B)
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Bunuel
The average (arithmetic mean) of 13 numbers is 70. If the average of 10 of these numbers is 90, what is the average of the other 3 numbers?


(A) \(-130\)

(B) \(\frac{10}{3}\)

(C) \(30\)

(D) \(90\)

(E) \(290\)


Total age of 13 people = 13*90 = 910

Total age of 10 people = 10*90 = 900

Difference of ages = 910 -900 = 10..........Total age of 3 people.

Average age of 3 people = 10 / 3.

The best answer is B.
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Bunuel
The average (arithmetic mean) of 13 numbers is 70. If the average of 10 of these numbers is 90, what is the average of the other 3 numbers?

(A) \(-130\)

(B) \(\frac{10}{3}\)

(C) \(30\)

(D) \(90\)

(E) \(290\)
\(?\,\,\, = \,\,\mu \,\left( {3\,\,{\text{left}}} \right)\)

By the homogeneity nature of the average, we proceed as follows:

\(\sum\nolimits_{\,13} {\, = } \,\,\,13 \cdot 70\)

\(\sum\nolimits_{\,10} {\, = } \,\,\,10 \cdot 90\)

\(\sum\nolimits_{\,13} { - \sum\nolimits_{\,10} \, } = \,\,\,700 + 210 - 900 = 10\)

\(? = \frac{{\sum\nolimits_{\,13} { - \sum\nolimits_{\,10} \, } }}{3} = \frac{{10}}{3}\)

The above follows the notations and rationale taught in the GMATH method.
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Bunuel
The average (arithmetic mean) of 13 numbers is 70. If the average of 10 of these numbers is 90, what is the average of the other 3 numbers?


(A) \(-130\)

(B) \(\frac{10}{3}\)

(C) \(30\)

(D) \(90\)

(E) \(290\)

\(\frac{13*70 - 10*90}{3}\)

\(= \frac{10}{3}\) , Answer must be (B)
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Bunuel
The average (arithmetic mean) of 13 numbers is 70. If the average of 10 of these numbers is 90, what is the average of the other 3 numbers?


(A) \(-130\)

(B) \(\frac{10}{3}\)

(C) \(30\)

(D) \(90\)

(E) \(290\)

We use the formula for the average: average = sum/number. We re-express the formula as sum = average x number.

The sum of the 13 numbers is 13 x 70 = 910, and the sum of 10 of the these numbers is 10 x 90 = 900. Thus the sum of the other 3 numbers is 910 - 900 = 10 and hence the average of these 3 numbers is 10/3.

Answer: B
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Theory

    ➡ Average = Sum of all the Values / Total Number of Values
    ➡ Sum of All the values = Average * Total Number of Values

The average (arithmetic mean) of 13 numbers is 70

Sum of 13 numbers = Average * 13 = 70 * 13 = 910

The average of 10 of these numbers is 90

Sum of 10 numbers = Average * 10 = 90 * 10 = 900

The average of the other 3 numbers

Average = Sum of 3 numbers / 3 = Sum of 13 numbers - Sum of 10 numbers/4 = \(\frac{910 - 900 }{ 3}\)
= \(\frac{10}{3}\)

So, Answer will be B.
Hope it helps!

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