Bunuel
The average (arithmetic mean) of a set of n numbers is 75. If adding the number 160 in the set raises the average to 80, what is the value of n?
A. 20
B. 16
C. 8
D. 6
E. 4
The average (arithmetic mean) of a set of n numbers is 75.We can write: (
sum of all n numbers)/n = 75
Multiply both sides of the equation by n to get:
sum of all n numbers = 75nAdding the number 160 in the set raises the average to 80Since we've added ONE number, we now have n + 1 numbers
And the SUM of these n+1 numbers = (
sum of the original n numbers) + 160
In other words, the SUM of these n+1 numbers =
75n + 160
If the new average of the n+1 number is
80, we can write: (
75n + 160)/(n + 1) =
80What is the value of n?Take: (
75n + 160)/(n + 1) =
80Multiply both sides by (n + 1) to get: 75n + 160 = 80(n + 1)
Expand: 75n + 160 = 80n + 80
Subtract 80 from both sides: 75n + 80 = 80n
Subtract 75n from both sides: 80 = 5n
Divide both sides by 5 to get: 16 = n
Answer: B
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