Bunuel wrote:
The average (arithmetic mean) of six numbers is 6. If 3 is subtracted from each of four of the numbers, what is the new average?
Let the numbers be a , b, c , d , e ,f
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average (arithmetic mean) of six numbers is 6.
So, Total of these 6 numbers must be 36
Or, a + b + c + d + e + f = 36
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3 is subtracted from each of four of the numbers
So, 12 must be subtracted from the total sum
i.e a + b + c + d + e + f - 12
Or, 36 - 12 = 24
Hence average of the 6 numbers now is 24/6 =>4
So, Answer will be (D) 4
PS : Ideally I like
Skywalker18 's method and will use the said method.
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