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The average (arithmetic mean) of six numbers is 6. If 3 is subtracted

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The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 03 Dec 2015, 06:23
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The average (arithmetic mean) of six numbers is 6. If 3 is subtracted from each of four of the numbers, what is the new average?

A. 1.5
B. 2
C. 3
D. 4
E. 4.5

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Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 03 Dec 2015, 06:26
subtracting 3 from each is as good as subtracting 3 from avg
so 6-3 =3

or else

since am is 6
sum =36
3 subtracted from each =36-18=18
new average 18/6 =3
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Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 03 Dec 2015, 07:18
1
Sum of 6 numbers = 6*6 =36
If 3 is subtracted from each of four of the numbers , we subtract 3*4=12 from the total sum
Sum of 6 number after subtracting 3 from each of four of the numbers = 36 - 12 = 24
New average = 24/6 = 4

Answer D
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Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 03 Dec 2015, 08:17
.Grr didn't read the question again :(
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Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 03 Dec 2015, 11:22
Bunuel wrote:
The average (arithmetic mean) of six numbers is 6. If 3 is subtracted from each of four of the numbers, what is the new average?


Let the numbers be a , b, c , d , e ,f

Quote:
average (arithmetic mean) of six numbers is 6.


So, Total of these 6 numbers must be 36

Or, a + b + c + d + e + f = 36

Quote:
3 is subtracted from each of four of the numbers


So, 12 must be subtracted from the total sum

i.e a + b + c + d + e + f - 12

Or, 36 - 12 = 24

Hence average of the 6 numbers now is 24/6 =>4

So, Answer will be (D) 4


PS : Ideally I like Skywalker18 's method and will use the said method.
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Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 10 Dec 2016, 05:54
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Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 11 Dec 2016, 02:22
Bunuel wrote:
The average (arithmetic mean) of six numbers is 6. If 3 is subtracted from each of four of the numbers, what is the new average?

A. 1.5
B. 2
C. 3
D. 4
E. 4.5


\(a + b + c + d + e + f = 30\)

Or, \(6 + 6 + 6 + 6 + 6 + 6 = 30\)

Quote:
If 3 is subtracted from each of four of the numbers


( 6 - 3 ) + ( 6 - 3 ) + ( 6 - 3 ) + ( 6 - 3 ) + 6 + 6 = 24

So, avergae will be 24/6 = 4

Hence, answer will be (D) 4


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Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted [#permalink]

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New post 09 Sep 2017, 07:47
D

sum/6=6
sum=36
36-12/6=24/6=4
Re: The average (arithmetic mean) of six numbers is 6. If 3 is subtracted   [#permalink] 09 Sep 2017, 07:47
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The average (arithmetic mean) of six numbers is 6. If 3 is subtracted

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