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Given data
(a+b)/2 = 8
(b+c)/2 = 13

From this a+b=16 & b+c=26
So, 16-a = 26-c(by equating the value of b in both the equation)
c-a = 10 which is the positive difference between a and c(Option C)


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a + b = 16
b + c = 26
add both the equations...
( a + b ) - ( b + c ) = 16 - 26

a - c = - 10

ans C
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Bunuel
The average (arithmetic mean) of two integers a and b is 8. If the average (arithmetic mean) of integers b and c is 13, what is the positive difference between a and c?

A. 26
B. 21
C. 10
D. 5
E. It cannot be determined from the information given.

We are given that the average of a and b is 8. Thus:

8 = (a + b)/2

16 = a + b

We are also given that the average of b and c is 13. Thus:

13 = (b + c)/2

26 = b + c

If we subtract 16 = a + b from 26 = b + c, we have:

10 = c - a

Answer: C
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Hi All,

It's looks like all of the other posters in this thread used an algebraic approach to this question, which is fine. It can also be solved rather easily by TESTing VALUES.

To start, we're told that the average (arithmetic mean) of two integers A and B is 8. This mean that the SUM of A and B is 16.

Let's TEST....
A = 0
B = 16

Next, we're told that the average (arithmetic mean) of integers B and C is 13. This means that the SUM of B and C is 26. Since we already have a value for B (it's 16), we now have a corresponding value for C...

C = 10

The question asks for the positive difference between A and C. Since A=0 and C=10, the positive difference is 10.

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