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Re: average problem [#permalink]
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gmat2012 wrote:
The average of 4 consecutive odd numbers is half that of the average of 5 consecutive even numbers. If the sum of these two average is 18, then the difference between the largest and smallest of these numbers is
a.10
b.21
c.7
d.13
e.5
please explain

Let odd numbers be 2n-3, 2n-1, 2n + 1, 2n + 3. Average = 2n.
Let even numbers be 2m- 4, 2m - 2, 2m, 2m + 2, 2m + 4. Average = 2m
it is given that 2m = 4n
Also 2n + 2m = 18 => 2n + 4n = 18.
6n = 18, 2n = 6 & 2m = 12. Largest = 16, smallest = 3.
Difference = 16 - 3 = 13.
hope this will help
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Re: average problem [#permalink]
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There's a simple solution to this.

To find the average for a set of consecutive numbers, you add the first and last terms and divide by 2. In other words, the average is essentially center/pivot point of the series, whether or not it is a number in the series. (e.g. 1, 3, 5, 7 - the average is 4)

Now we look at the other information given. the average of the odd series is half the average of the even series and they sum up to 18. So let e be the average of the even series. We get 1.5e = 18
=> e = 12

12 will be the middle term of the series and since there are 5, we now know the series look like this: (8, 10, 12, 14, 16)
12/2 = 6, the pivot point of the odd series, since there are 4, we know the series look like this: (3, 5, 7, 9)

16 - 3 = 3.

QED.
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Re: average problem [#permalink]
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thanatoz wrote:
There's a simple solution to this.

To find the average for a set of consecutive numbers, you add the first and last terms and divide by 2. In other words, the average is essentially center/pivot point of the series, whether or not it is a number in the series. (e.g. 1, 3, 5, 7 - the average is 4)

Now we look at the other information given. the average of the odd series is half the average of the even series and they sum up to 18. So let e be the average of the even series. We get 1.5e = 18
=> e = 12

12 will be the middle term of the series and since there are 5, we now know the series look like this: (8, 10, 12, 14, 16)
12/2 = 6, the pivot point of the odd series, since there are 4, we know the series look like this: (3, 5, 7, 9)

16 - 3 = 3.

QED.

good thought, i essentially solved using conventional method like assuming even and odd series numbers.. thanks for giving different prospective to the solution.
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Re: average problem [#permalink]
Is there a different approach to this problem? I find the explanations above tough!! :-(
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The average of 4 consecutive odd numbers is half that of the [#permalink]
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The average of 4 consecutive odd numbers is half that of the average of 5 consecutive even numbers. If the sum of these two average is 18, then the difference between the largest and smallest of these numbers is

A. 10
B. 21
C. 7
D. 13
E. 5

odd average=(4x+12)/4=x+3
even average=(5y+20)/5=y+4
y+4=2(x+3)➡2x-y=-2
(x+3)+(y+4)=18➡x+y=11
adding, 3x=9
x=3
y=11-3=8
8+4*2=16
16-3=13
D.
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Re: The average of 4 consecutive odd numbers is half that of the [#permalink]
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Clearly there are two equations possible.
And by the averages' property -
1.x=y/2 and x+y=18 Solving- x=6x=6and y=12.
Now the highest and lowest - 16 and 3.
So 16-3=13
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Re: The average of 4 consecutive odd numbers is half that of the [#permalink]
Set odd average A, even average B, then per the problem:

A+B = 18 and

A = B/2

Substituting:

A = 6, B = 12

Odd series contains an even number of elements so the average is 1/2 sum of 2nd and 3rd terms, making the series:

3,5,7,9

Even series contains an even number of elements, making the average, 12, the 3rd term, making the series:

8,10,12,14,16

16-3=13

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Re: The average of 4 consecutive odd numbers is half that of the [#permalink]
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