Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
55% (01:59) correct
45%
(02:22)
wrong
based on 363
sessions
History
Date
Time
Result
Not Attempted Yet
The average speed of Salem Express train is 60 kmph. if the halts at various stations is excluded then the average speed is 80 kmph. What is the average halt time (in hours) per hour of Salem Express train?
A. 0.20
B. 0.25
C. 0.30
D. 0.35
E. 0.40
(Source : Wizako)
A. 0.20
B. 0.25
C. 0.30
D. 0.35
E. 0.40
(Source : Wizako)
03 Nov 2024, 10:37
Kudos
Bookmarks
Another method could be:
without halt time: D = 80*t
with halt time: D = 60* (t+x)
-> with t being the total time the train is in motion and x being the total halting time
As D is equal in both cases, we can put the remaining equal:
80t = 60 * (t+x)
We are looking for the ratio of the halt time (=x) to the total time of the trip (=t+x). If we change the equation accordingly we will get t/(t+x)
t/(t+x) = 60/80 = 3/4
If the ratio of t to the total time is 3/4, then the ratio of x to the total time must be the remaining: 1- 3/4= 1/4 = 0.25
Hence (B)
without halt time: D = 80*t
with halt time: D = 60* (t+x)
-> with t being the total time the train is in motion and x being the total halting time
As D is equal in both cases, we can put the remaining equal:
80t = 60 * (t+x)
We are looking for the ratio of the halt time (=x) to the total time of the trip (=t+x). If we change the equation accordingly we will get t/(t+x)
t/(t+x) = 60/80 = 3/4
If the ratio of t to the total time is 3/4, then the ratio of x to the total time must be the remaining: 1- 3/4= 1/4 = 0.25
Hence (B)
General Discussion
