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The figure above represents a circular garden, with center O, surround

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The figure above represents a circular garden, with center O, surround  [#permalink]

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New post 27 Dec 2015, 10:53
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Difficulty:

  5% (low)

Question Stats:

86% (01:08) correct 14% (01:19) wrong based on 43 sessions

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The figure above represents a circular garden, with center O, surrounded by a circular walkway that is 4 feet wide. What is the area of the walkway, in square feet?

A. 16π
B. 25π
C. 81π
D. 88π
E. 169π

Attachment:
2015-12-27_2152.png
2015-12-27_2152.png [ 37.85 KiB | Viewed 1347 times ]

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Re: The figure above represents a circular garden, with center O, surround  [#permalink]

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New post 27 Dec 2015, 22:14
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Bunuel wrote:
Image
The figure above represents a circular garden, with center O, surrounded by a circular walkway that is 4 feet wide. What is the area of the walkway, in square feet?

A. 16π
B. 25π
C. 81π
D. 88π
E. 169π

Attachment:
2015-12-27_2152.png


13^2 * π =169π

9^2 * π = 81π

169π -81π =88π

D. 88π
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Re: The figure above represents a circular garden, with center O, surround  [#permalink]

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New post 30 Dec 2015, 11:39
1
Hi All,

This prompt is an example of a 'punch out' question. We'll need to find the total area (of everything), then 'punch out' the area of the part that we DON'T WANT - what's left will be the area of what we DO want.

The big circle has a radius of 13 (the 'inner' radius of 9 + the 4 that represents the width of the walkway). It's area is...

Area = pi(R^2) = pi(13^2) = 169pi

Since we want the area of the walkway, we have to 'punch out' the area of the inner circle. That circle's area is...

Area = pi(R^2) = pi(9^2) = 81pi

Thus, the area of the walkway is.... 169pi - 81pi = 88pi

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Re: The figure above represents a circular garden, with center O, surround  [#permalink]

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New post 13 Nov 2019, 20:28
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Re: The figure above represents a circular garden, with center O, surround   [#permalink] 13 Nov 2019, 20:28
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