Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options. - Dec 21
11:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
22 Oct 2019, 22:13
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (01:11) correct
15%
(01:19)
wrong
based on 53
sessions
History
Date
Time
Result
Not Attempted Yet
The figure above represents a triangular field. What is the minimum distance, in meters, that a person would have to walk to go from point A to a point on side BC?
A. 50
B. 60
C. 70
D. 80
E. 90
Attachment:
traingle.jpg [ 5.11 KiB | Viewed 2068 times ]
22 Oct 2019, 22:19
Kudos
Bookmarks
Bunuel
The figure above represents a triangular field. What is the minimum distance, in meters, that a person would have to walk to go from point A to a point on side BC?
A. 50
B. 60
C. 70
D. 80
E. 90
Attachment:
traingle.jpg
drop a perpendicular D from A to side BC ; BC = 80 ; AC= 100 and AD =60
∆ 5:4:3 ;
IMO B ; 60
29 Oct 2019, 12:29
Kudos
Bookmarks
The triangle has two sides with equal length. Their opposite angles must therefore also be of opposite length. We can conclude that this is an isosceles triangle.
The shortest way is a straight line from A to the line BC which is the height of the triangle. We call it D. D splits the triangle in two identical triangle, creating a 90° angle. This lets us apply the Pythagoras Theorem a^2 + b^2 = c^2.
In this case this would be a^2 + 80^2 = 100^2. As a result, solving for a, we get a = 60. The answer is B
The shortest way is a straight line from A to the line BC which is the height of the triangle. We call it D. D splits the triangle in two identical triangle, creating a 90° angle. This lets us apply the Pythagoras Theorem a^2 + b^2 = c^2.
In this case this would be a^2 + 80^2 = 100^2. As a result, solving for a, we get a = 60. The answer is B
