Last visit was: 11 Dec 2024, 20:28 It is currently 11 Dec 2024, 20:28
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,115
Own Kudos:
17,795
 [1]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,115
Kudos: 17,795
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,115
Own Kudos:
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,115
Kudos: 17,795
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Rohit2015
Joined: 20 Jul 2015
Last visit: 09 Apr 2020
Posts: 24
Own Kudos:
Given Kudos: 7
Posts: 24
Kudos: 24
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,696
Own Kudos:
Given Kudos: 165
Expert reply
Posts: 3,696
Kudos: 18,288
Kudos
Add Kudos
Bookmarks
Bookmark this Post

Solution



Given
In this question, we are given that
    • ABCD is a given parallelogram, in which point E lies on the side BC
    • Line DE bisects ∠D
    • Also, BE = DE and ∠A = 120

To find
We need to determine
    • The measure of ∠BDE

Approach and Working out
Let us assume that ∠BDE = p.
    • As BE = DE, ∠BDE = ∠DBE = p
    • Hence, ∠BED = 180 – (p + p) = 180 – 2p
    • Therefore, ∠DEC = 180 – ∠BED = 180 – [180 – 2p] = 2p

Now, because ABCD is a parallelogram, we can say ∠A = ∠C = 120

Considering the triangle DEC,
    • 120 + p + 2p = 180
    Or, p = 20

Thus, option A is the correct answer.

Correct Answer: Option A
Moderator:
Math Expert
97815 posts