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Attachment:
10.24ps(a).png
10.24ps(a).png [ 17.3 KiB | Viewed 1924 times ]

Since the length of the arc \(AB\) is equal to the length of the arc \(AC, <AOB = <AOC = (\frac{1}{2})(360°-100°) = 130°\).
Since \(OA=OC\) in the triangle \(AOC\), we have \(<OCA = (\frac{1}{2})(180°-130°) = 25°.\)

Therefore, C is the answer.
Answer: C
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MathRevolution
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Attachment:
10.24ps(a).png

Since the length of the arc \(AB\) is equal to the length of the arc \(AC, <AOB = <AOC = (\frac{1}{2})(360°-100°) = 130°\).
Since \(OA=OC\) in the triangle \(AOC\), we have \(<OCA = (\frac{1}{2})(180°-130°) = 25°.\)

Therefore, C is the answer.
Answer: C


Hi MathRevolution,
Thank you for your question and the subsequent solution, but without mentioning that O is the center of the circle how can you say that OA=OC?
The question should have mentioned that O is the center of the circle.
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stne
MathRevolution
=>

Attachment:
10.24ps(a).png

Since the length of the arc \(AB\) is equal to the length of the arc \(AC, <AOB = <AOC = (\frac{1}{2})(360°-100°) = 130°\).
Since \(OA=OC\) in the triangle \(AOC\), we have \(<OCA = (\frac{1}{2})(180°-130°) = 25°.\)

Therefore, C is the answer.
Answer: C


Hi MathRevolution,
Thank you for your question and the subsequent solution, but without mentioning that O is the center of the circle how can you say that OA=OC?
The question should have mentioned that O is the center of the circle.

You are right.
The center O should be mentioned in the question for clear understanding.
The question is updated.
Thank you for your comments.
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