Last visit was: 12 Dec 2024, 04:50 It is currently 12 Dec 2024, 04:50
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 12 Dec 2024
Posts: 97,842
Own Kudos:
685,244
 [2]
Given Kudos: 88,254
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,842
Kudos: 685,244
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
avatar
RajatVerma1392
Joined: 08 Jan 2018
Last visit: 18 Nov 2020
Posts: 29
Own Kudos:
143
 [3]
Given Kudos: 12
Location: India
GPA: 4
WE:Information Technology (Computer Software)
Posts: 29
Kudos: 143
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
TheNightKing
Joined: 18 Dec 2017
Last visit: 20 Mar 2024
Posts: 1,154
Own Kudos:
Given Kudos: 421
Location: United States (KS)
GMAT 1: 600 Q46 V27
GMAT 1: 600 Q46 V27
Posts: 1,154
Kudos: 1,133
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
stne
Joined: 27 May 2012
Last visit: 11 Dec 2024
Posts: 1,736
Own Kudos:
Given Kudos: 645
Posts: 1,736
Kudos: 1,644
Kudos
Add Kudos
Bookmarks
Bookmark this Post
RajatVerma1392
f(x) = a*x^2

As per question:
1. A = (1.5,9)
=> f(1.5) = a * \((1.5)^2\)
=> 9 = a * 2.25
=> a = 4
Thus C => 4*\((2.5)^2\)
Sufficient.

2. B = (2,16)
=> f(2) = a * \(2^2\)
=> 16 = 4*a
=> a =4
Thus C => 4*\((2.5)^2\)
Sufficient.

IMO the answer is D.

Please hit kudos if you like the solution.

I think in the question it should have been mentioned that "a" is a constant.
avatar
RajatVerma1392
Joined: 08 Jan 2018
Last visit: 18 Nov 2020
Posts: 29
Own Kudos:
Given Kudos: 12
Location: India
GPA: 4
WE:Information Technology (Computer Software)
Posts: 29
Kudos: 143
Kudos
Add Kudos
Bookmarks
Bookmark this Post
TheNightKing
RajatVerma1392
f(x) = a*x^2

As per question:
1. A = (1.5,9)
=> f(1.5) = a * \((1.5)^2\)
=> 9 = a * 2.25
=> a = 4
Thus C => 4*\((2.5)^2\)
Sufficient.

2. B = (2,16)
=> f(2) = a * \(2^2\)
=> 16 = 4*a
=> a =4
Thus C => 4*\((2.5)^2\)

Sufficient.

IMO the answer is D.

Please hit kudos if you like the solution.

My Question is did you solve it or you knew you will be able to find individually and marked D? Since this is a DS question and not PS

I have solved it, because we need to find one value which is unique and gives the values for C. This is one way to solve questions like these, IMO it does not matter whether it is a DS or PS queston.
avatar
RajatVerma1392
Joined: 08 Jan 2018
Last visit: 18 Nov 2020
Posts: 29
Own Kudos:
Given Kudos: 12
Location: India
GPA: 4
WE:Information Technology (Computer Software)
Posts: 29
Kudos: 143
Kudos
Add Kudos
Bookmarks
Bookmark this Post
stne
RajatVerma1392
f(x) = a*x^2

As per question:
1. A = (1.5,9)
=> f(1.5) = a * \((1.5)^2\)
=> 9 = a * 2.25
=> a = 4
Thus C => 4*\((2.5)^2\)
Sufficient.

2. B = (2,16)
=> f(2) = a * \(2^2\)
=> 16 = 4*a
=> a =4
Thus C => 4*\((2.5)^2\)
Sufficient.

IMO the answer is D.

Please hit kudos if you like the solution.

I think in the question it should have been mentioned that "a" is a constant.

Yes,It should be stated, but we can also see that for that type of graph there should be one constant that will move the graph in a direction, otherwise if f(x)= \(x^2\), then that graph should be a parabola, but again we should know whether it is a downward or upward parabola, for that we need some constant.
Moderator:
Math Expert
97842 posts