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The Middlebury train station is between the Appleton and

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VP
Joined: 21 Jul 2006
Posts: 1452
The Middlebury train station is between the Appleton and [#permalink]

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16 Aug 2008, 07:46
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The Middlebury train station is between the Appleton and Lancaster stations and all three are serviced by the same track. What is the distance between Middlebury and Lancaster?

(1) If a train can travel 50 miles on one pound of coal, it will use twice as much coal traveling from MiddleBury to Lancaster as it will use to travel between Middlebury and Appleton.

(2) Traveling from Appleton to Middlebury at an average rate of 35 mph takes 30 minutes longer than at an average rate of 55 mph.

thanks

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Director
Joined: 27 May 2008
Posts: 531
Re: DS: Distance [#permalink]

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16 Aug 2008, 07:58
tarek99 wrote:
The Middlebury train station is between the Appleton and Lancaster stations and all three are serviced by the same track. What is the distance between Middlebury and Lancaster?

(1) If a train can travel 50 miles on one pound of coal, it will use twice as much coal traveling from MiddleBury to Lancaster as it will use to travel between Middlebury and Appleton.

(2) Traveling from Appleton to Middlebury at an average rate of 35 mph takes 30 minutes longer than at an average rate of 55 mph.

thanks

statement 1 : AM = 2x and ML = x, AL = 3x... not suff
statement 2 : AM/35 - AM/55 = 0.5, we can find AM but we have to find ML ... not suff

combine : ML = AM/2 ... suff
C
Senior Manager
Joined: 19 Mar 2008
Posts: 344
Re: DS: Distance [#permalink]

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16 Aug 2008, 10:21
The Middlebury train station is between the Appleton and Lancaster stations and all three are serviced by the same track. What is the distance between Middlebury and Lancaster?

(1) If a train can travel 50 miles on one pound of coal, it will use twice as much coal traveling from MiddleBury to Lancaster as it will use to travel between Middlebury and Appleton.

(2) Traveling from Appleton to Middlebury at an average rate of 35 mph takes 30 minutes longer than at an average rate of 55 mph.
------------------------
(1) does not give nay info on the actual cost used. Insufficient. Not sufficient.

(2) we have no info about the distance between M and L. Not sufficient.

(1) + (2)
From (2), assume distance from A to M is D
D = 35(t + 0.5) = 55(t)
35t + 35/2 = 55t
20t = 35/2
t=35/40=7/8
D = 55 *(7/8)

From (1)
assume distance from M to L is E
E = 2D
E = 110*(7/8)

Sufficient

(C)
VP
Joined: 21 Jul 2006
Posts: 1452
Re: DS: Distance [#permalink]

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16 Aug 2008, 13:56
OA is C. I chose B because I assumed that M is exactly in the middle. I guess when we are told that M is between the other 2 stations, that doesn't necessarily mean that it is exactly in the middle, but rather anywhere between the 2 stations. cool so i know where i made my mistake.
thanks guys

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: DS: Distance   [#permalink] 16 Aug 2008, 13:56
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The Middlebury train station is between the Appleton and

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