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11 Jun 2019, 01:49
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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62% (01:35) correct
38%
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The point that bisects the line depicted in the figure above is:
A. (1.25 ; 0.75)
B. (1.25 ; 2.25)
C. (1.25 ; 2)
D. (1.25 ; 1.25)
E. (1.5 ; 1.25)
Attachment:
image521.jpg [ 3.63 KiB | Viewed 2903 times ]
11 Jun 2019, 02:00
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By property of similar triangles, we can visualize a smaller right angled triangle with in a larger right angled triangle with the depicted line as hypotenuse.
Hence, the opposite sides and adjacent sides of the smaller triangle will be half as much as the larger one.
With coordinates from Option "A", it is possible to visualize.
Posted from my mobile device
Hence, the opposite sides and adjacent sides of the smaller triangle will be half as much as the larger one.
With coordinates from Option "A", it is possible to visualize.
Posted from my mobile device
11 Jun 2019, 06:30
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Bunuel
The point that bisects the line depicted in the figure above is:
A. (1.25 ; 0.75)
B. (1.25 ; 2.25)
C. (1.25 ; 2)
D. (1.25 ; 1.25)
E. (1.5 ; 1.25)
Attachment:
image521.jpg
The only point on the line segment that would bisect it is its mid point
--> Midpoint of 2 points (x1, y1) and (x2, y2) = (\(\frac{(x1 + x2)}{2}\), \(\frac{(y1 + y2)}{2}\))
--> Midpoint of (0, -1.5) and (2.5, 3) = (\(\frac{(0 + 2.5)}{2}\), \(\frac{(-1.5 + 3)}{2}\))
= (1.25, 0.75)
IMO Option A
Pls Hit Kudos if you like the solution
