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# The revenue, R, from selling a certain type of flower varies with the

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Math Expert
Joined: 02 Sep 2009
Posts: 55609
The revenue, R, from selling a certain type of flower varies with the  [#permalink]

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02 Jan 2018, 23:45
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Difficulty:

15% (low)

Question Stats:

85% (01:12) correct 15% (01:05) wrong based on 132 sessions

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The revenue, R, from selling a certain type of flower varies with the price per flower according to the equation $$R = –40(p – 3)^2 + 360$$. What price per flower, p, should be charged to achieve the highest revenue?

A. $36 B.$12
C. $3 D.$2
E. $1 _________________ Retired Moderator Joined: 25 Feb 2013 Posts: 1210 Location: India GPA: 3.82 Re: The revenue, R, from selling a certain type of flower varies with the [#permalink] ### Show Tags 03 Jan 2018, 03:42 Bunuel wrote: The revenue, R, from selling a certain type of flower varies with the price per flower according to the equation R = –40(p – 3)2+ 360. What price per flower, p, should be charged to achieve the highest revenue? A.$36
B. $12 C.$3
D. $2 E.$1

Hi Bunuel

Kindly confirm whether the highlighted part is $$(p-3)^2$$ or is it simply $$(p-3)*2$$ because in either case answer will be different.
Math Expert
Joined: 02 Sep 2009
Posts: 55609
Re: The revenue, R, from selling a certain type of flower varies with the  [#permalink]

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03 Jan 2018, 03:46
niks18 wrote:
Bunuel wrote:
The revenue, R, from selling a certain type of flower varies with the price per flower according to the equation R = –40(p – 3)2+ 360. What price per flower, p, should be charged to achieve the highest revenue?

A. $36 B.$12
C. $3 D.$2
E. $1 Hi Bunuel Kindly confirm whether the highlighted part is $$(p-3)^2$$ or is it simply $$(p-3)*2$$ because in either case answer will be different. It's $$R = –40(p – 3)^2 + 360$$. Edited. Thank you. _________________ Retired Moderator Joined: 25 Feb 2013 Posts: 1210 Location: India GPA: 3.82 Re: The revenue, R, from selling a certain type of flower varies with the [#permalink] ### Show Tags 03 Jan 2018, 04:16 Bunuel wrote: The revenue, R, from selling a certain type of flower varies with the price per flower according to the equation $$R = –40(p – 3)^2 + 360$$. What price per flower, p, should be charged to achieve the highest revenue? A.$36
B. $12 C.$3
D. $2 E.$1

To maximize $$R$$ we need to minimize $$-40(p-3)^2$$ which is a negative value irrespective of $$p$$

Hence at $$p=3$$; $$-40(p-3)^2=0$$ hence $$R=360$$

Option C
Status: Preparing for GMAT
Joined: 25 Nov 2015
Posts: 1025
Location: India
GPA: 3.64
Re: The revenue, R, from selling a certain type of flower varies with the  [#permalink]

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03 Jan 2018, 09:41
Bunuel wrote:
The revenue, R, from selling a certain type of flower varies with the price per flower according to the equation $$R = –40(p – 3)^2 + 360$$. What price per flower, p, should be charged to achieve the highest revenue?

A. $36 B.$12
C. $3 D.$2
E. $1 $$R = –40(p – 3)^2 + 360$$ To achieve the maximum revenue, we must decrease the term $$–40(p – 3)^2$$, which becomes zero when p=3. Answer C. _________________ Please give kudos, if you like my post When the going gets tough, the tough gets going... Manager Joined: 12 Apr 2017 Posts: 72 Location: United States Concentration: Finance, Operations GPA: 3.1 Re: The revenue, R, from selling a certain type of flower varies with the [#permalink] ### Show Tags 01 Dec 2018, 10:05 Great question! I had to stop and think and not just pick an answer. Answer is C, just plugging in the answers you get C at$360, which is the max.

A & B, result in negative values > than 360.
Re: The revenue, R, from selling a certain type of flower varies with the   [#permalink] 01 Dec 2018, 10:05
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