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The sequence S is defined as follows for all n ≥ 1: The sum of the [#permalink]
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Bunuel wrote:
The sequence S is defined as follows for all n ≥ 1:

\(S_n=(-1)^n*\frac{1}{n(n+1)}\)

The sum of the first 10 terms of S is:

(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1


Hi,
i would do this Q in two steps...
1) first step would be to eliminate all wrong answers..
as we can see the first term is negative ,next +ive and so on.. basically all odd numbers are -ive and even numbers are +ive..
Also the denominator is increasing in subsequent term, so the answer has to be a negative number that is <0..
only A and B are left..
2) second step to close on the answer between the two requires a bit of calculations...
\(\frac{1}{(n(n+1))}\)=\(\frac{1}{n}-\frac{1}{(n+1)}\)...
so first two terms give us=\(-1+\frac{1}{2}+\frac{1}{2}-\frac{1}{3}=-\frac{1}{3}\)..
next two terms=\(-\frac{1}{3}+\frac{1}{4}+\frac{1}{4}-\frac{1}{5}=-\frac{1}{30}\)...
we can see the vaue gets significantly smaller with every next two terms so we can estimate that the answer will be slightly lesser than -1/3 but should be more than -1/2..
so ans B.. we can actually next two terms as -1/105.. and can find other two to get to exact answer but may not require that..
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Re: The sequence S is defined as follows for all n ≥ 1: The sum of the [#permalink]
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The sequence S is defined as follows for all n ≥ 1:

\(S_n=(-1)^n*\frac{1}{n(n+1)}\)

The sum of the first 10 terms of S is:

(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1


Solution -

S1 = -1/2
S2 = 1/6
S3 = -1/12
S4 = 1/20 .....

Neglecting the remaining terms as fractions does not vary the sum more than 1%. [We do not have time to calculate all in GMAT test]

S=S1+S2+S3+S4...S10 > -1/3, but S<-1/4 .

-1/3 <S< -1/4. So answer falls in B.

Thanks,

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Re: The sequence S is defined as follows for all n ≥ 1: The sum of the [#permalink]
Expert Reply
balamoon wrote:
The sequence S is defined as follows for all n ≥ 1:

\(S_n=(-1)^n*\frac{1}{n(n+1)}\)

The sum of the first 10 terms of S is:

(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1


Solution -

S1 = -1/2
S2 = 1/6
S3 = -1/12
S4 = 1/20 .....

Neglecting the remaining terms as fractions does not vary the sum more than 1%. [We do not have time to calculate all in GMAT test]

S=S1+S2+S3+S4...S10 > -1/3, but S<-1/4 .

-1/3 <S< -1/4
. So answer falls in B.

Thanks,

Kudos Please.


I think the highlighted part in your above mentioned explanation is INCORRECT.

The actual Sum of the series is -0.3821789 which does NOT satisfy the range -1/3 <S< -1/4
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Re: The sequence S is defined as follows for all n ≥ 1: The sum of the [#permalink]
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lets check first 4 terms only ,
S1 = -1/2
S2 = 1/6
S3 = -1/12
S4 = 1/20

Add S1 and S2 , = -1/3
So sum of every term in series is negative so sum of entire first 10 term is negative ... this eliminates option C, D , E

Now S1+S2 = -1/3 = -0.333
after this terms are only going get smaller and smaller . The sum of next 8 terms can not shoot this value beyond -0.50 because then in that case sum (s3 +s4+ ..... +s10) should constiute more than 30% of (S1 to S10) , which looks imposible as values will get smaller and smaller only .

So total should lie between 0 and -1/2.
Answer B
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Re: The sequence S is defined as follows for all n ≥ 1: The sum of the [#permalink]
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Bunuel wrote:
The sequence S is defined as follows for all n ≥ 1:

\(S_n=(-1)^n*\frac{1}{n(n+1)}\)

The sum of the first 10 terms of S is:

(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1


MANHATTAN GMAT OFFICIAL SOLUTION:

We should compute the first few elements of Sn. Because we need to know the sum of the first 10 elements, we should also track the cumulative sum:

By now (if not before!) the pattern should be fairly obvious. The sum of the first n terms of Sn converges somewhere in the range between –0.3667 and –0.4. Only (B) exhibits a range in which the sum of this series could converge.

The correct answer is B.

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Re: The sequence S is defined as follows for all n ≥ 1: The sum of the [#permalink]
Bunuel wrote:
The sequence S is defined as follows for all n ≥ 1:

\(S_n=(-1)^n*\frac{1}{n(n+1)}\)

The sum of the first 10 terms of S is:

(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1


sum = 1/2 last+first * number of term
i choose 1 and then put 10 and according to formula got -54/110 and my naswer is b
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Re: The sequence S is defined as follows for all n 1: The sum of the [#permalink]
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