The table in the figure below shows the amount of waste material in po

For family A we have : \(\frac{30}{100}\)

family B :\(\frac{22}{50}\)

family C :\(\frac{7}{20}\)

family D:\(\frac{30}{55}\)

family E:\(\frac{4}{10}\)

in order to simplify the above fractions, we will multiply each of them with 100. Thus the required ratio for each of them becomes,

family A: \((\frac{30}{100})100\) \(= 30\)

family B :\((\frac{22}{50})100\) \(= 44\)

family C :\((\frac{7}{20})100\) \(= 35\)

family D:\((\frac{30}{55})100\) \(= 54\)

family E:\((\frac{4}{10})100\) \(= 40\)

hence answer must be D.

Also, by carefully observing all the numerators, we will notice that only for family D numerator is more than 50% of the denominator. hence we can easily shun all the calculations that we have done in the previous steps and straightaway mark D as the answer.